Some electromagnetism questions

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Can anyone please answer, and if possible, explain, this question? Thanks

1. A battery is connected between A and B of a bar made of semi-conductor of type P. The positive electrode was connected in A and the negative in B. What's the current direction?

A. from A to B
B. in the semiconductor it cannot pass any current
C. it depends on the type of the battery
D. it depends on the emf of the battery
E. from B to A
 
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I'll give you a hint: The electric field goes from positive to negative potential. Now, what is the definition of current? Also, how does current flow in a semiconductor?
 
That being said, I guess it's A.

Since it's being applied a corrent from the battery in point A, the positive pole of the semiconductor P, it will increase the potential there forcing some electrons to pass through.

If the semiconductor was of type N, the asnwer would be B, right?

I still have some confusion about this. The sole existence of a semiconductor of type P without the N-semiconductor it's kind of weird, since in most examples I have seen (not too many, though), they are almost coupled together...
 
nunos said:
That being said, I guess it's A.

Since it's being applied a corrent from the battery in point A, the positive pole of the semiconductor P, it will increase the potential there forcing some electrons to pass through.

If the semiconductor was of type N, the asnwer would be B, right?

I still have some confusion about this. The sole existence of a semiconductor of type P without the N-semiconductor it's kind of weird, since in most examples I have seen (not too many, though), they are almost coupled together...

I'm not so sure about your statement about n-type semiconductors. It's been a while since I studied semiconductors, but doping a semiconductor, whether P or N-doping, should, if anything, increase its conductivity.

I believe the answer is A.
 
Thanks espen 180 for your help. I can imagine how boring it might be for someone who is into physics to help a noob like me with such simple questions. I will keep this topic open if I have any more doubt.
 
I can imagine how boring it might be...

Not at all. :) It's actually one of my main pasttimes.
 
Another question:

An alpha particle is formed by 2 protons and 2 neutrons. If this one alpha particle moves with velocity 6.15e5 m/s in a direction perpendicular to a magnetic field |B| = 0.27T, what's the value of the magnetic force in the particle?

So I suppose the formula to use is the Lorentz Formula:

[tex]\stackrel{\rightarrow}{F} =q(\stackrel{\rightarrow}{E} + \stackrel{\rightarrow}{v} \times \stackrel{\rightarrow}{B})[/tex]

Since the electric field is non-existent and q = 4 times the mass of a proton

[tex]F = 6.69*10^{-27}*6.15*10^{5}\times 0.27 = 1.1*10^{-21}N[/tex]

Which is wrong, because the correct solution is [tex]5.3*10^{-14}N[/tex]

I suppose the problem is with the cross product... Any help is greatly appreciated. Thanks.
 
The charge of an alpha particle is 2e, not 4e. (Two protons and two neutrons.)
 
I need some help with my physics ?'s?!
Can anyone help me?
 
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