Calculating Electric Flux and Net Force on Charged Particles | Homework Help

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The discussion revolves around calculating the electric flux and net forces on charged particles. The total electric flux from a cubical box measuring 34.0 cm on each side is given as 1.29 x 10^3 N·m²/C, prompting the question of the enclosed charge using Gauss' Law. Additionally, three charged particles at the corners of an equilateral triangle are analyzed for the net forces acting on them, with specific charges provided. Participants express confusion over calculations and seek clarification on the application of formulas, particularly regarding the constants and dimensions involved. The thread emphasizes the need for clear calculations and proper use of symbols in physics equations.
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Homework Statement



The total electric flux from a cubical box 34.0 cm on a side is 1.29 x 103 N·m2/C. What charge is enclosed by the box?

----and----

Three charged particles are placed at the corners of an equilateral triangle of side d = 1.00 m (Fig. 16-53). The charges are Q1 = +4.0 µC, Q2 = -6.0µC, and Q3 = -6.0 µC. Calculate the magnitude and direction of the net force on each due to the other two.
16-53alt.gif

Figure 16-53
Force on Q1: N at ° counterclockwise from +x axis (to the right)
Force on Q2: N at ° counterclockwise from +x axis (to the right)
Force on Q3: N at ° counterclockwise from +x axis (to the right)

Homework Equations


Gauss' Law (I think)(I don't know how to type those symbols out sooo)

----and----

I'm not really sure on this one. I've tried setting it up F=(k)(d^2/|Q(#)Q(#)) to find the magnitude but that isn't working (or at least my numbers are weird for it)

The Attempt at a Solution


I tried to multiply (1.29
multiply.gif
103 N·m2/C)(8.85e-12) but that didn't work? Do I (and if it is needed) how do I incorporate the 34cm?

----and----

See above
 
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One question per post please.

Can you show some actual calculation results? "that didn't work" or "that isn't working" doesn't tell us much.

You can find most of the symbols you need by selecting the Sigma icon from the editing menu bar:
Fig1.gif
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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