Some help with MIPS assembly code

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The discussion revolves around a MIPS assembly code snippet and the user's difficulty in understanding its functionality and expected output. The code initializes two registers, $t0 and $t1, with hexadecimal values and performs a bitwise AND operation, storing the result in $t2. The Bgtz instruction checks if $t2 is greater than zero and, if true, branches to a label for further instructions. The user seeks clarification on the purpose of the code and specific instructions, particularly the meaning of "add 1" in the context of the Bgtz instruction. Responses confirm that the user needs to compute the value of $t2 by executing the code, emphasizing that the instructions are valid and should lead to an understanding of the final value in $t2.
XodoX
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Hey guys. I'm trying to practice some basic MIPS, but I can't seem to get this right. You just plug in the number and then you follow the code and you'll get obviously the end result. I can't get the result for these here. Does anybody know? I'd really appreciate help. Thank you!

1. $t0 = 0x55555555
$t1= 0x12345678

And $t2, $t0, $t1
Bgtz $t2, add 1
J end
Add0: addi $t0, $t0, 0
Add1: addi $t1, $t1, 1
Add2 : addi $t2, $t2, 2

End:


Value of $t2 is needed
 
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What is this code supposed to do?

Not being familiar with MIPS programming I have a couple of questions:
1. What is the "1." doing in the first line?
2. Is it valid to have "add 1" in the Bgtz instruction?
 
Just means #1 as in problem 1, sorry for the confusion.

And yes, it's valid. Just got to plug it in and get the value of t2.
 
XodoX said:
Just means #1 as in problem 1, sorry for the confusion.

And yes, it's valid. Just got to plug it in and get the value of t2.
I don't understand. What do you mean "just got to plug it in and get the value of t2."

Also, what is this chunk of code intended to do?
Code: 
$t0 = 0x55555555
$t1= 0x12345678

And $t2, $t0, $t1
Bgtz $t2, add 1
J end 
Add0: addi $t0, $t0, 0
Add1: addi $t1, $t1, 1
Add2 : addi $t2, $t2, 2

End:
 

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