Some number belongs to real such that

[lovemake1]

Homework Statement

sin(x) = x - 1

Homework Equations

The Attempt at a Solution

i used the fact that -1 < sin(x) < 1
and set interval to [0, 2pi].

this gave me,

-1 < sin(x) < 1 and -1 < x - 1 < 2pi - 1
so therefore, since sin(x) < 1 < 2pi - 1
there must be x, real number that lies between -1 and 1.


is this correct?

 

[D H]

Draw a graph of y=sin(x) versus y=x-1.

 

[micromass]

You are correct in proving that such a x exists. Do you also need to find that x? That seems a bit difficult...

 

[D H]

There is no such x between -1 and 1. That is not to say that such an x does not exist.