Some questions about the Lambert W function

  • Context: Graduate 
  • Thread starter Thread starter dimension10
  • Start date Start date
  • Tags Tags
    Function
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 3K views
dimension10
Messages
371
Reaction score
0
I was wondering, what would be the solution for [tex]\lim_{x \rightarrow -\infty} W(x)[/tex] where W(x) is the Lambert-W function.

Wolfram|Alpha gives the result [tex]\infty[/tex] but the graph certainly does not imply this (In fact,[tex]\lim_{x\rightarrow \infty} x\,\exp(x)=\infty[/tex]) I only graphed it it between -10 and 10 and behind -1.5 or so, the graph goes straight down so you can't even see the function beyond -1.75 or so. Does the function make a sharp turn somewhere else behind? Is the function even continuous?

Also,

[tex]\lim_{\omega \rightarrow -\infty} \omega \,\exp(\omega)=0[/tex] and [tex]\lim_{\omega\rightarrow 0} \omega\,\exp(\omega)=0[/tex]. So does this imply that [tex]W(0)=0 \mbox{ and } W(-\infty)=0[/tex].

And one final question, Wolfram|Alpha gives a long complicated result for the inverse function of x^x involving the Lambert W function. How does one use the Lambert W function to do so?

Thanks.
 
Last edited:
Physics news on Phys.org
For the real branches of the Lambert Function, [itex]W_{0}(x)[/itex] or [itex]W_{-1}(x)[/itex], the limit doesn't exist. The plot of x Exp[x] never dips down to -Infinity, so there is no limit. In fact, these two branches are only defined on the range [itex]x \geq -1/e[/itex]. The complex branches may have a limit as x tends to -Infinity. That may be the result that wolframalpha is giving you.

As for x = y^y, write this as x = exp[y ln y] and then take the log of both sides. Then note that y = e^(ln y). (There are some other subtleties regarding branches of the complex logarithm, but this is the basic result).
 
Mute said:
For the real branches of the Lambert Function, [itex]W_{0}(x)[/itex] or [itex]W_{-1}(x)[/itex], the limit doesn't exist. The plot of x Exp[x] never dips down to -Infinity, so there is no limit. In fact, these two branches are only defined on the range [itex]x \geq -1/e[/itex]. The complex branches may have a limit as x tends to -Infinity. That may be the result that wolframalpha is giving you.

As for x = y^y, write this as x = exp[y ln y] and then take the log of both sides. Then note that y = e^(ln y). (There are some other subtleties regarding branches of the complex logarithm, but this is the basic result).

Thanks