Some trigonometric, exponential thing?

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Discussion Overview

The discussion revolves around the equivalence of trigonometric and exponential forms of functions, specifically in the context of the expression f(x) = A'sin(kx) + B'cos(kx) and its equivalent f(x) = Ae^{ikx} + Be^{-ikx}. Participants explore the implications of using Euler's formula and the conditions under which each form is applicable, particularly in relation to physical scenarios such as potential wells and free particles.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants question how the trigonometric and exponential forms are equivalent, particularly in light of Euler's formula.
  • There is a discussion about the nature of the coefficients A and B, with some suggesting that they cannot both be real.
  • One participant proposes that the exponential form is an alternative to the trigonometric form, especially in contexts involving complex solutions.
  • Another participant emphasizes the utility of using complex exponentials when dealing with complex solutions, while real exponentials or trigonometric forms may be preferred for real solutions.

Areas of Agreement / Disagreement

Participants express differing views on the equivalence of the two forms and the conditions under which each should be used. There is no consensus on whether one form is superior to the other, as the discussion remains unresolved regarding the implications of using either representation.

Contextual Notes

Limitations include the lack of clarity on the specific conditions under which the equivalence holds, as well as the dependence on the nature of the coefficients A and B. The discussion also touches on the relevance of these forms in specific physical contexts, but does not resolve the mathematical intricacies involved.

Who May Find This Useful

This discussion may be useful for students and practitioners in physics and engineering who are exploring the relationships between trigonometric and exponential functions, particularly in the context of wave functions and quantum mechanics.

M. next
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How can we say:

f(x)=A'sin(kx)+B'cos(kx)

or equivalently

f(x)=Ae[itex]^{ikx}[/itex]+Be[itex]^{-ikx}[/itex]??

How are these two equivalent knowing that e[itex]^{ix}[/itex]=cosx+isinx

I don't get this?
 
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Hi M. next! :smile:
M. next said:
How can we say:

f(x)=A'sin(kx)+B'cos(kx)

or equivalently

f(x)=Ae[itex]^{ikx}[/itex]+Be[itex]^{-ikx}[/itex]??

How are these two equivalent knowing that e[itex]^{ix}[/itex]=cosx+isinx

I don't get this?

They won't both be real.

Try Euler's formula

what do you get? :smile:
 
it would be: A(coskx +isinkx)+B(coskx-isinkx)
which's (A+B)coskx+i(A-B)sinkx
.. A'coskx+iB'sinkx
where's did the "i" go?
 
M. next said:
it would be: A(coskx +isinkx)+B(coskx-isinkx)
which's (A+B)coskx+i(A-B)sinkx

so B' = i(A-B) …

i told you they won't both be real! :biggrin:
 
Sorry, i didn't check the site from since, I had some connection difficulties.
So, my final question, can this be done? Is the exponential form an alternative for the known trigonometric one?
And why do I use it? Why not keep it in trigonometric form. I am working on potential wells, free particles and so, if this information would help you answer my question.
 
Hi M. next! :smile:
M. next said:
Is the exponential form an alternative for the known trigonometric one?
And why do I use it? Why not keep it in trigonometric form.

Yes, they're equally valid alternatives.

You use cos and sin, or real exponentials, if you're only interested in real solutions,

but you use complex exponentials if you're interested in complex solutions. :wink:
 
Thanks, am grateful
 

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