Sound wave intensity of elephants

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SUMMARY

The discussion focuses on calculating the intensity level of infrasound produced by elephants, which can reach 103dB at a distance of 5.0m. The intensity at this level is determined to be 0.0199 W/m². To find the intensity level at a distance of 10km, participants suggest using the inverse square law, represented by the equation I1/R1² = I2/R2², followed by converting the resulting intensity into decibels using the formula B=10log(I/10^-12).

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  • Understanding of sound intensity and decibel levels
  • Familiarity with the inverse square law in physics
  • Knowledge of logarithmic functions and their applications
  • Basic principles of sound propagation in a medium
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  • Study the inverse square law in acoustics
  • Learn how to convert intensity to decibels using the formula B=10log(I/10^-12)
  • Research the properties of infrasound and its applications in animal communication
  • Explore sound intensity measurement techniques and tools
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Students studying physics, acoustics researchers, wildlife biologists, and anyone interested in animal communication and sound propagation.

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Homework Statement



There is evidence that elephants communicate via infrasound, generating rumbling vocalizations as low as 14hz that can travel up to 10km. The intensity level of these sounds can reach 103dB, measured a distance of 5.0m from the source. Deteremine the intensity level of the infrasound 10km from the source, assuming the sound energy radiates uniformly in all directions.


Homework Equations



B=10log(I/10^-12)

The Attempt at a Solution



i found the intensity at an intensity level of 103dB to be.0199W/m^2. I'm just not sure where to go from here. Suggestions would be appreciated.

thanks
 
Physics news on Phys.org
Intensityi is inversly proportional to square of the distance.
Using I1/R1^2 = I2/R2^2, find I2. Then convert it into dB.
 

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