Calculating Sound Wave Intensity and Decibels 10.0m from Source

In summary: MIn summary, a source of sound emits 5.0 mW of acoustic power uniformly in all directions. The intensity of this sound wave at a distance of 10.0 m from the source is 4 x 10^-6 W/m^2. The sound level in decibels at the same distance is 66 dB. The intensity is calculated by considering the spherical shape of the sound wave and the power it carries. The sound level is determined using the equation L=20log_10 (p1/p0), where p1 is the acoustic pressure and p0 is the reference value.
  • #1
jamessmith
3
0
A source of sound emits 5.0 mW of acoustic power uniformly in all directions.

1. Calculate the intensity of this sound wave 10.0 m from the source.
2. Find the sound level in decibles 10.0 m from the source.

Answers:
1. 4 x 10^-6 W/m^2 ---- I don't know how to get this answer.
2. 66 dB --- I don't know how to get this answer.
 
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  • #2
I don't really feel like calculating, but the idea behind this problem is very simple.
Consider a spherical loudspeaker, which probably doesn't exist, but it would definitely emit the sound in all directions. Thus, the acoustic wave would form a sphere. The power, that the wave carries with itself is constant, in this case it's your 5mW. The intensity you are supposed to calculate is the amount of power per square meter. 10.0m from the source the acoustic wave forms a sphere with radius=10 m. Now you just need to calculate the area of such spere and you should get the correct answer.

Now, having calculated that, you have to know what sound level (in dB) is. Mathematically, the equation is L=20log_10 (p1/p0). p1 is the acoustic pressure of the wave. You have been given the acoustic power of the wave. Now, according to the deffinition, P=W/t, but W=F*S (excuse this mid-school notation :P), hence P=F*S/t; but S/t=v, which is the velocity of the acoustic wave in the air-constant. Thus F=P/v. To get the pressure, divide by the area again. p0 is the refference value (dunno what it's called in English) equal to 2*10^(-5) Pa.

Hope it helps,
greets
 

1. What is the formula for calculating sound wave intensity?

The formula for sound wave intensity is I = P/A, where I is the intensity in watts per square meter, P is the power of the sound source in watts, and A is the area in square meters at which the sound is being measured.

2. How is sound wave intensity measured?

Sound wave intensity is measured using a sound level meter, which detects and measures the pressure of sound waves in a specific area. The results are typically displayed in decibels (dB).

3. What is the relationship between sound wave intensity and distance from the source?

The intensity of sound waves decreases as the distance from the source increases. This is due to the spreading out of the sound waves as they travel through space, resulting in a decrease in energy per unit area.

4. How is the decibel scale used to measure sound intensity?

The decibel (dB) scale is a logarithmic scale used to measure sound intensity. It quantifies the ratio between a given sound level and a reference sound level, which is typically the threshold of human hearing. A difference of 10 dB represents a 10-fold difference in sound intensity.

5. What is the maximum intensity of sound waves that can be heard by the human ear?

The maximum intensity of sound waves that can be heard by the human ear is approximately 120 dB. This is considered the threshold of pain and can cause damage to the ear if exposed for a prolonged period of time.

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