Sound waves question - vibrations and amplitudes

Click For Summary

Homework Help Overview

The discussion revolves around a tuning fork that vibrates 235 times in 3.1 seconds, with a specified amplitude of 0.59 mm. Participants are exploring concepts related to frequency, period, and the distance traveled by the fork's tines over time.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss calculating frequency and period based on the tuning fork's vibrations and time. There are questions about the interpretation of distance traveled in relation to amplitude and equilibrium position, as well as the number of amplitudes in a vibration.

Discussion Status

Some participants have provided calculations for frequency and period, while others are questioning the assumptions regarding distance traveled and the definition of amplitude in this context. There is a mix of interpretations being explored, particularly concerning how to measure distance traveled in relation to oscillation periods.

Contextual Notes

There is uncertainty regarding the starting point for measuring distance traveled, whether from equilibrium or maximum displacement. Additionally, participants are navigating differing interpretations of the relationship between amplitude and distance traveled in one second.

FlorenceC
Messages
24
Reaction score
0
A tuning fork vibrates 235 times in 3.1 seconds with an amplitude of 0.59mm. Determine..
i) its frequency
ii) its period
iii) the distance the end of one of the fork tines travels in one second

for i) The answer I got is f=75.81Hz
ii) The answer I got is 0.13s
iii) ?
 
Physics news on Phys.org
hz is 1/s so 235/3.1s

period is 1/frequency s
 
You may want to check your calculation for part (ii) again! I think it is 0.013s
 
I think a little more info is needed for part (iii) because you don't know where it is starting from. Do we want to find the distance it travels after 1 second from it's equilibrium position or from its maximum displacement?
 
ofeyrpf said:
I think a little more info is needed for part (iii) because you don't know where it is starting from. Do we want to find the distance it travels after 1 second from it's equilibrium position or from its maximum displacement?

I'm going to guess equilibrium, since this is only gr. 11 physics. The supply teacher said there are 4 amplitudes in 1 vibration, so the distance is 4*0.59*frequency. I tried it, but I got an unreasonable answer and I don't think there are 4 amplitudes in a vibration.
 
FlorenceC said:
I'm going to guess equilibrium,
Another reasonable guess is that it means on average (which is fact what you computed).
The supply teacher said there are 4 amplitudes in 1 vibration, so the distance is 4*0.59*frequency. I tried it, but I got an unreasonable answer and I don't think there are 4 amplitudes in a vibration.
Starting from equilibrium, how far will it travel in the first quarter period? How far in the second quarter?
What answer did you get?
 
haruspex said:
Another reasonable guess is that it means on average (which is fact what you computed).
Starting from equilibrium, how far will it travel in the first quarter period? How far in the second quarter?
What answer did you get?

First quarter = 44.73 mm
Second quarter = 89.4 6mm
 
FlorenceC said:
First quarter = 44.73 mm
Second quarter = 89.4 6mm
How did you get those numbers? The amplitude is only 0.59 mm.
 
haruspex said:
How did you get those numbers? The amplitude is only 0.59 mm.

For the first quarter, there is 1 amplitude, so (1*0.00059*75.81)
For the second quarter, there are 2 amplitude, so (2*0.00059*75.81)

I multiplied by the frequency to get the answer for 1 second.
 
  • #10
Displacement is not the same as the distance travelled. If you go to school 500 m far, you walk 500 m and your displacement is also 500 m. If you go there and back, your displacement is zero, but you walked 1000 m, your "distance travelled" or "distance covered" is 1000 m. The tip of the fork travels from equilibrium to maximum displacement (amplitude) during a quarter of the period. Then it moves backwards, reaching zero displacement in quarter period again, but traveling A distance again, so the distance traveled in half period is 2A. The whole distance traveled in one period is 4A. The number of periods in one second is equal to the frequency. So the total distance traveled in one second is? ehild
 

Attachments

  • tunefork.JPG
    tunefork.JPG
    5.3 KB · Views: 486
  • #11
ehild said:
Displacement is not the same as the distance travelled. If you go to school 500 m far, you walk 500 m and your displacement is also 500 m. If you go there and back, your displacement is zero, but you walked 1000 m, your "distance travelled" or "distance covered" is 1000 m. The tip of the fork travels from equilibrium to maximum displacement (amplitude) during a quarter of the period. Then it moves backwards, reaching zero displacement in quarter period again, but traveling A distance again, so the distance traveled in half period is 2A. The whole distance traveled in one period is 4A. The number of periods in one second is equal to the frequency. So the total distance traveled in one second is?


ehild

so the answer is 4*0.00059*75.81 = .1789m or 178.9mm
 
  • #12
FlorenceC said:
so the answer is 4*0.00059*75.81 = .1789m or 178.9mm

Yes it is, but round it to three significant digits.

ehild
 
  • #13
FlorenceC said:
For the first quarter, there is 1 amplitude, so (1*0.00059*75.81)
For the second quarter, there are 2 amplitude, so (2*0.00059*75.81)

I multiplied by the frequency to get the answer for 1 second.
I had asked how far in one quarter period, i.e. one quarter of a complete oscillation.
You had expressed doubts that it traveled four amplitudes in each period; I was trying to get you to see that it does.
 
  • #14
ehild said:
Yes it is, but round it to three significant digits.

ehild

haruspex said:
I had asked how far in one quarter period, i.e. one quarter of a complete oscillation.
You had expressed doubts that it traveled four amplitudes in each period; I was trying to get you to see that it does.

I finally understand it now. Thank you so much ehild and haruspex.
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
3
Views
1K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
20
Views
5K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K