Sources of musical sound problem

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The discussion focuses on calculating the lengths of two organ pipes based on their fundamental and harmonic frequencies. For pipe A, the fundamental frequency of 450 Hz leads to a length of approximately 0.381 meters, derived from the formula f = v/2L. Pipe B, which has one end open, requires a different approach for its length calculation, specifically using the relationship between harmonics. The user initially attempted to set an equality for the lengths but encountered errors in their algebra. Clarification on the correct method for calculating pipe B's length is sought, emphasizing the need to apply the wavelength concept accurately.
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Question: Organ pipe A, with both ends open, has a fundamental frequency of 450 Hz. The third harmonic of organ pipe B, with one end open, has the same frequency as the second harmonic of pipe A. Use 343 m/s for the speed of sound in air.
a)How long is pipe A?

b)How long is pipe B?

I found the length of pip a by f=v/2L, or 450=343/2L, L=343/900, which is correct.

I thought I could find the length of pipe B by setting an equality like this: (5v/4L)=(2v/2(.381)). I am pretty sure I did the algebra correctly but got an incorrect answer. Any help would be greatly appreciated...
 
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Fundamental frequency of pipe A = 450/s
First harmonic " = 900/s
Second harmonic " = 1350/s

Fundamental length of pipe B = 1/4 wavelength
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Length of pipe B for 3d harmonic = 7/4 wavelength

Solve just as you solved for the length of pipe A
 
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