Spacetime curvature and curvature index

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SUMMARY

The discussion centers on the relationship between spacetime curvature and the curvature index of space, specifically in the context of the cosmological constant (Λ). It establishes that while both spacetime curvature, described as a tensor, and the curvature index (k) can provide insights into the universe's geometry, they do not necessarily agree. The curvature index can take values of +1, 0, or -1, while a flat universe is characterized by Ω = 1, which corresponds to k = 0. The fate of the universe cannot be determined solely based on these parameters without understanding the distribution of energy content.

PREREQUISITES
  • Understanding of cosmological parameters such as Ω (density parameter) and Λ (cosmological constant).
  • Familiarity with concepts of spacetime curvature and tensor mathematics.
  • Knowledge of the curvature index (k) and its implications for the geometry of the universe.
  • Basic principles of general relativity and its application to cosmology.
NEXT STEPS
  • Study the implications of the cosmological constant (Λ) on the geometry of the universe.
  • Explore the mathematical formulation of spacetime curvature using tensor calculus.
  • Investigate the relationship between energy density and critical energy density in cosmology.
  • Learn about the Friedmann equations and their role in determining the fate of the universe.
USEFUL FOR

Astronomers, cosmologists, and physics students interested in the geometric properties of the universe and the implications of cosmological parameters on its evolution.

Ranku
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TL;DR
What is the difference between spacetime curvature and curvature index of space?
The presence of the cosmological constant produces a flat spacetime universe with Ω = 1. There is also the curvature index of space k, which can be +1, 0, -1. But it is possible to have any of these values of k with Λ > 0 or Λ < 0. How is the curvature of spacetime determined by Λ different from that of the curvature index of space k?
 
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Spacetime curvature is a tensor. The curvature index is a normalised description of the curvature of a homogeneous and isotropic spatial hypersurface.
 
Orodruin said:
Spacetime curvature is a tensor. The curvature index is a normalised description of the curvature of a homogeneous and isotropic spatial hypersurface.
Could you elaborate a bit more, in terms of how is it that spacetime curvature and curvature index of space don't have to agree, and yet each is supposedly uniquely describing the curvature and fate of the universe?
 
They do not have to agree because they are completely different things.
 
Orodruin said:
They do not have to agree because they are completely different things.
So, with Ω = 1, which describes a flat universe, and suppose k= +1, which describes a closed universe, what would be the fate of such a universe?
 
If ##\Omega = 1##, then ##k = 0##. You cannot say what is the fate unless you know how the energy content splits into components.
 
Orodruin said:
If ##\Omega = 1##, then ##k = 0##. You cannot say what is the fate unless you know how the energy content splits into components.
If Ω = 1, then k = 0, then that implies a consistent correlation, even if they are "completely different things". I am trying to understand that.
 
Ranku said:
If Ω = 1, then k = 0, then that implies a consistent correlation, even if they are "completely different things". I am trying to understand that.
##\Omega## is not the spacetime curvature. It is the energy density divided by the critical energy density. The critical energy density is defined as the energy density at which ##k = 0##.
 

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