Spacetime Interval Relativity question.

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SUMMARY

The discussion revolves around calculating the time interval measured by a clock traveling at a speed of 0.6c between two events that are 5 seconds apart in time and 3 seconds apart in space. The relevant equation is delta(s)^2 = delta(t)^2 - delta(d)^2, which leads to a calculated interval of 4 seconds when considering the clock's velocity. The participants clarify that the moving clock's measurement must account for its speed, indicating the importance of relativistic effects in time measurement.

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Homework Statement


Two events occur 5 s apart in time and 3 s apart in space. A clock traveling at a speed of .6 can be present at both these events. What time interval will such a clock measure between the events?
A. 8 s
B. 5.8 s
C. 5 s
D. 4 s
E. 2 s
F. Other


Homework Equations



I know delta(s)^2=delta(t)^2 - delta(d)^2, but I don't know how the clock's velocity plays into the problem.

The Attempt at a Solution


If you just use the equation above delta(s) comes out to be 4 s, but is that taking into account the fact that the clock is moving at .6?
 
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Welcome to PF!

Hi PhantomFX! Welcome to PF! :smile:
PhantomFX said:
… What time interval will such a clock measure between the events?

Hint: what distance interval will it measure? :wink:
 

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