Special Relativity and time dilation

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SUMMARY

The discussion centers on calculating the time dilation effect experienced by two spaceships traveling at a relative velocity of 1.2x10^8 m/s, utilizing the Lorentz Factor formula. Participants confirm that the clocks on each ship will disagree by a factor of approximately 1.291, indicating that each captain perceives the other's clock as ticking more slowly. The factor is dimensionless, as it represents a ratio of two time intervals. Participants emphasize the importance of correctly applying the Lorentz Factor in special relativity calculations.

PREREQUISITES
  • Understanding of special relativity concepts
  • Familiarity with the Lorentz Factor formula
  • Basic knowledge of relative velocity
  • Ability to perform algebraic calculations
NEXT STEPS
  • Study the derivation of the Lorentz Factor in detail
  • Explore examples of time dilation in various frames of reference
  • Learn about the implications of time dilation in GPS technology
  • Investigate the effects of relativistic speeds on mass and energy
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Students of physics, educators teaching special relativity, and anyone interested in the practical applications of time dilation in modern technology.

mikil100
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Homework Statement



Two spaceships are traveling with a relative velocity of 1.2x10^8 m/s, both carrying clocks.
According to the captain of each ship, the other captains clock ticks more slowly than his own. By what factor do the clocks disagree?

Homework Equations



1/(1-(v^2/c^2))^1/2

The Attempt at a Solution


The only formula I can think of that brings up the time dilation going on is the Lorenz Factor, as the only given value is the relative velocity of each ship. I interpreted this question as the ships are speeding at a little over 1/3 of the speed of light past each other if they are using each other as a frame of reference, So I simply plugged the velocity (which is relative to each captain, using the other ship as a reference frame) into the equation to get... so the clocks disagree by a factor of 1.291... I am not sure what units I would even place there or if it is just a number with no units.

Is this the correct line of thinking?
 
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Yes, you are right on track and the factor has no units because it is a ratio of two times.
I get a different number for the answer. I'm old and out of practise so you are probably correct, but do run it through again to check.
 

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