Special Relativity: Time Dilation and the Twin Paradox

Click For Summary
SUMMARY

The discussion focuses on the calculations of time dilation in special relativity, specifically involving a spaceship traveling at 0.99c. The Lorentz gamma factor is calculated to be 7.088, leading to the conclusion that 1 minute on the spaceship corresponds to 7.088 minutes on Earth. Conversely, when considering 3 minutes on Earth, the spaceship observers perceive the event duration as longer, confirming that both sets of observers see each other's clocks as running slow due to time dilation.

PREREQUISITES
  • Understanding of Lorentz transformations
  • Familiarity with the concept of time dilation
  • Basic knowledge of inertial reference frames
  • Ability to perform calculations using the Lorentz gamma factor
NEXT STEPS
  • Study the derivation and implications of the Lorentz gamma factor
  • Explore the concept of simultaneity in special relativity
  • Learn about the twin paradox and its resolutions
  • Investigate practical applications of time dilation in modern physics
USEFUL FOR

Students of physics, educators teaching special relativity, and anyone interested in understanding the implications of time dilation and the twin paradox.

the riddick25
Messages
24
Reaction score
0

Homework Statement


there is a spaceship passing the Earth at a speed of 0.99c. if something takes 1 minute (according to the spaceship), how long does this take according to a clock on the earth.

and also, if something takes 3 minutes (according to the earth), how long will pass according to the spaceship


Homework Equations


Lorentz gamma factor
t=gamma x t'

The Attempt at a Solution



then i first did it, i worked out my gamma factor to be 7.088, which is corect.
when i did the first question, i found t to be 7.088 x 1 = 7.088 minutes

the second bit i am struggling with, firstly i thought it was going to be less, due to the fact the spaceship is moving, and therefore experiences time dialation. but now i am unsure.
if the person on the spaceship is in an inertial frame, it sees the Earth moving past at 0.99c, so it would see the event happen over a longer time like question 1.
could someone please help me with this, i know its probably that i haven't grasped something simple, but i would like to know

here are the two solutions, 0.42 mins if it is shorter, and 21.264 mins if it is the other.

i'm new to this forum, so sorry if i missed something
 
Physics news on Phys.org
Both sets of observers see each other's clocks as running slow. Time dilation works both ways. If something takes 3 minutes according to an Earth clock, then the spaceship observers will say it took longer.
 
thanks a million :)
 

Similar threads

Replies
6
Views
2K
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 67 ·
3
Replies
67
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
36
Views
4K