Calculating Velocity and Time Dilation in Special Relativity

Click For Summary

Homework Help Overview

The problem involves a spaceship traveling a distance of six light-years from Earth, with a focus on calculating its velocity and the time experienced in different reference frames according to the principles of special relativity.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the variables involved, questioning whether they are solving for u or v, and how to apply the relevant equations. There is an exploration of combining equations to derive a value for u.

Discussion Status

Some participants have provided hints and guidance on how to approach the problem, while others express uncertainty about their methods. There is an ongoing exploration of different interpretations and approaches to the calculations.

Contextual Notes

Participants are working within the constraints of the problem statement and the equations of special relativity, with some expressing confusion about the variables and their relationships.

struggles
Messages
49
Reaction score
0

Homework Statement


  1. A spaceship travels from Earth to the vicinity of the star that is measured by astronomers on Earth to be six light-years away. The spaceship and its occupants have a total rest mass of 32 000 kg. Assume that the spaceship travels at constant velocity. The time taken as measured by clocks on the spaceship is 2.5 years.
    1. (i) Compute the velocity of the spaceship. [3 marks]
    2. (ii) How long does the trip take as measured by clocks in the Earth’s

      inertial rest frame? [3 marks]

Homework Equations



x' = γ(x-ut)
t' = γ(t - ux/c2) where the dash frame is the object rest frame, u is the relative speed between frames
γ = 1/√(1-u2/c2)
v' = v-u/1-u2v/c2

The Attempt at a Solution



So I'm a bit stuck my the first part of the question.
So far I have determined that x = 6ly, t' = 2.5yrs. I'm getting a bit puzzled as to what I'm looking to find. Is it u
or v or are they the same thing in this case? regardless I cannot think of a way in which i have enough variables that allows me to compute a value. Any help would be greatly appreciated!
 
Physics news on Phys.org
Sometimes you have to chip away at it. See if you can solve for x'. (Hint: You'll need a different version of your first equation.)

struggles said:
I'm getting a bit puzzled as to what I'm looking to find. Is it u
or v or are they the same thing in this case?
You are solving for u. v is irrelevant: there's only one velocity in this problem.
 
Ok so I'm not sure if this works or not but this is what I've got:
t = γt' and t = x/u.
Combining this gives x/t' = uγ and then expanding this all out and rearranging gives a value for u. Would this method work?
 
struggles said:
Ok so I'm not sure if this works or not but this is what I've got:
t = γt' and t = x/u.
Combining this gives x/t' = uγ and then expanding this all out and rearranging gives a value for u. Would this method work?
That will do it. Good! :thumbup:
 
Thank you for your help!
 

Similar threads

Replies
6
Views
2K
Replies
7
Views
2K
  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
17
Views
2K