High School Using SR & Curved Coordinates for Time Calculation

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SUMMARY

The discussion centers on calculating proper time in an accelerated frame of reference using Special Relativity (SR) with curved coordinates. It is established that the Lorentz transformation is not applicable in this context, as it pertains only to inertial frames. Instead, the proper time can be calculated using the formula τ = ∫(t1 to t2) √(1 - v(t)²/c²) dt, where v(t) is the velocity of the observer. The integration of this expression provides the necessary proper time without the need for General Relativity (GR) mechanics.

PREREQUISITES
  • Understanding of Special Relativity (SR)
  • Familiarity with proper time calculations
  • Knowledge of curved coordinate systems
  • Basic calculus for integration
NEXT STEPS
  • Study the derivation of the proper time formula τ = ∫(t1 to t2) √(1 - v(t)²/c²) dt
  • Explore the concept of arc length (ds²) in curved coordinates
  • Learn about the limitations of Lorentz transformations in non-inertial frames
  • Investigate applications of proper time in accelerated reference frames
USEFUL FOR

Physicists, students of relativity, and anyone interested in the mathematical foundations of time calculations in accelerated frames will benefit from this discussion.

sqljunkey
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Someone told me that I don't need the whole mechanics of GR to be able to calculate the proper time in an accelerated frame of reference. I can just use SR but with curved coordinates and then integrate for time. But he didn't give me a reference where I could find the formula to do this. How do you use Lorentz transformation with curved coordinates? Is this true? Anyone has a reference for it?

Thanks
 
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sqljunkey said:
Someone told me that I don't need the whole mechanics of GR to be able to calculate the proper time in an accelerated frame of reference. I can just use SR but with curved coordinates and then integrate for time. But he didn't give me a reference where I could find the formula to do this.
You can use equation 2 here:

https://en.m.wikipedia.org/wiki/Proper_time

You need to have ##ds^2## which is known as the arc length, as well P, both in terms of the chosen coordinates.
 
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sqljunkey said:
How do you use Lorentz transformation with curved coordinates?
You don't. The Lorentz transformation is, by definition, a transformation between inertial frames. However, you do not even need curvilinear coordinates to compute proper times of accelerated observers. You can just apply
$$
\tau = \int_{t_1}^{t_2} \sqrt{1 - v(t)^2/c^2}\, dt.
$$
However, you can of course define a coordinate system where your accelerated observer is at rest, but you do not need to.
 
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In case Orodruin's answer isn't clear, he is noting that if your velocity in some inertial coordinate system is ##v## at coordinate time ##t## then in the elementary time from ##t## to ##t+dt## your clock advances ##d\tau=dt/\gamma##, then integrating. Or you can start from the expression for the interval and get the same result.
 
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