Specific Gravity and antifreeze

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SUMMARY

The discussion focuses on calculating the specific gravity of a mixture formed by combining 5.0L of antifreeze solution with a specific gravity of 0.8 and 4.0L of water. The specific gravity (SG) is defined as the ratio of the density of a substance to the density of water, which is 1 g/cm³. The final specific gravity of the 9.0L mixture can be determined using the formula SG = density of substance / density of water, where the densities are derived from the specific gravities of the components.

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  • Understanding of specific gravity and its calculation
  • Knowledge of density and its units (g/cm³)
  • Familiarity with volume conversions (L to mL)
  • Basic algebra for solving equations
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  • Calculate the density of the antifreeze solution using its specific gravity
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Homework Statement


If 5.0L of antifreeze solution (0.8 specific gravity) is mixed with 4L of water to make a 9.0 L mixture. what is the specific gravity of the mixture?


Homework Equations


SG = density of substance / density of water


The Attempt at a Solution


I am confused as in how to gain the density from the substance gravity. Is it given that the density is 1 g/cm^3 for water?
 
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Use CGS system -- there the specific gravity is numerically equal to the density in gm/cc.
1 L = 1000 cc = 1000 mL.
 

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