Checking my answer/approach - specific gravity of a mixture

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SUMMARY

The specific gravity of a mixture consisting of 40% ethyl alcohol and 60% water is calculated to be 0.916. The density of ethyl alcohol is established as 0.79 g/mL, while the density of water is 1 g/mL. By assuming a total volume of 100 mL for the mixture, the mass of the components is determined: 60 g for water and 31.6 g for ethyl alcohol. The resulting density of the mixture is confirmed to be 0.916, leading to the conclusion that the specific gravity is also 0.916 when compared to water.

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  • Understanding of specific gravity and density concepts
  • Basic knowledge of volume and mass calculations
  • Familiarity with the properties of ethyl alcohol and water
  • Ability to perform cross multiplication in equations
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Chemistry students, educators, and professionals involved in fluid dynamics or material science will benefit from this discussion, particularly those focusing on the properties of liquid mixtures.

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Homework Statement


What is the specific gravity of a mixture 40% ethyl alcohol and 60% water? The specific gravity of ethyl alcohol is 0.79.

Homework Equations


The Attempt at a Solution


He showed us a way to do it for another type of problem but I approached it a bit differently and I wanted to make sure my answer was logical/correct before submitting it. So what I did was this:

Assume 100 mL of mixture. Then you have 40 mL alcohol, 60 mL water.
Density of water = 1 = mass/60 mL; mass of water therefore = 60 g
0.79 = density of alcohol/density of water (1), so density of alcohol = 0.79
I set up a cross multiplication:

0.79 g/1 mL = x g/40 mL
I got 31.6 g of ethyl alcohol.

So the total mass of the mixture is 91.6 g.

Thus the density of the mixture is 91.6 g/100 mL = 0.916

Thus specific gravity of the mixture = 0.916/1 = 0.916.

Does this seem accurate?
 
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Yes, that's right, if the 60% and 40% were by volume.
 

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