What is the absolute pressure in a tank measured by a manometer?

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SUMMARY

The absolute pressure in a tank measured by a manometer is calculated using the formula P = P atm + pgh, where P atm is the local atmospheric pressure, p is the density of the manometer fluid, and h is the height of the fluid column. In this case, the specific gravity of the fluid is 0.85, leading to a density of 850 kg/m³. Given an atmospheric pressure of 96 kPa and a manometer column height of 55 cm, the absolute pressure within the tank is determined to be 100.6 kPa.

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Homework Statement


A manometer is used to measure the pressure of a gas in a tank. The fluid used has a the specific gravity of 0.85, and the manometer column height is 55 cm, as shown in figure 3-20. If the local atmospheric pressure is 96 kPa, determine the absolute pressure within the tank.

Homework Equations


P = SG x p

P = P atm + pgh

The Attempt at a Solution


SOLUTION.

The reading of manometer attached to a tank is to be determined.

Assumptions The density of a gas in the tanks is much lower than the density of the manometer fluid.

Properties The specific gravity of the manometer fluids is given to be 0.85. We take the standard density of water to be 1000kg/m³.

Analysis The density of the fluid is obtained by multiplying its specific gravity by the density of water,

P = SG ( p H2O ) = (0.85)(1000kg/m³) = 850 kg/m³

P = P atm + pgh

= 96 kPa + (850kg/m³)(9.81m/s²)(0.55m) x (1N/1kg.m/s^2)(1kPa/1000N/m^2)

= 100.6 kPa

*edit I figured it out
 
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Looks correct, to me.
 

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