Calculate Resultant Temperature: 100g Steam at 100°C + 500g Ice at -20°C

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SUMMARY

The discussion centers on calculating the resultant temperature when 100g of steam at 100°C is mixed with 500g of ice at -20°C. The key equation used is Q = mCΔT, where Q represents heat transfer, m is mass, C is specific heat capacity, and ΔT is the change in temperature. Participants emphasize the importance of understanding phase changes and the specific heat capacities of water, steam, and ice to arrive at the correct resultant temperature. The consensus is that both steam and ice will transition to water, impacting the final temperature calculation.

PREREQUISITES
  • Understanding of the heat transfer equation Q = mCΔT
  • Knowledge of specific heat capacities for water, steam, and ice
  • Familiarity with phase changes of water (melting and vaporization)
  • Basic thermodynamics principles
NEXT STEPS
  • Study the specific heat capacity values for water, steam, and ice
  • Learn about the latent heat of fusion and vaporization
  • Explore detailed examples of heat transfer calculations involving phase changes
  • Review thermodynamic principles related to energy conservation in closed systems
USEFUL FOR

Students in physics or chemistry, educators teaching thermodynamics, and anyone interested in understanding heat transfer and phase changes in water.

Rishabh0110
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1. The problem
What is the resultant temperature when 100g of steam at 100°C is passed through 500g of ice at -20°C.

Homework Equations


Q=mCDeltaT[/B]

The Attempt at a Solution


I am not sure whether both the quantities will combine to from water
 
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Rishabh0110 said:
I am not sure whether both the quantities will combine to from water
What are your thoughts? Forum rules require you to try and show us what you have tried.
 

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