- #1

zooboodoo11

- 4

- 0

**1.Speedboat**

A speedboat with a length of 10.2m and a mass of 247 kg is negotiaging a circular turn (radius = 33 m) around a buoy. During the turn, the engine causes a net tangential force of magnitude 521 N to be applied to the boat. The intial speed of the boat going into the turn is 4 m/sec.

a) What is the tangential acceleration of the boat, 2 sec into the turn?

aT = m/sec2 *

b) What is the tangential velocity of the boat, 2 sec into the turn?

vT = m/sec *

8.2 OK

c) What is the centripetal acceleration, 2 sec into the turn?

acen = m/sec2

528 NO

d) What is the total acceleration, 2 sec into the turn?

a = m/sec2

A speedboat with a length of 10.2m and a mass of 247 kg is negotiaging a circular turn (radius = 33 m) around a buoy. During the turn, the engine causes a net tangential force of magnitude 521 N to be applied to the boat. The intial speed of the boat going into the turn is 4 m/sec.

a) What is the tangential acceleration of the boat, 2 sec into the turn?

aT = m/sec2 *

b) What is the tangential velocity of the boat, 2 sec into the turn?

vT = m/sec *

8.2 OK

c) What is the centripetal acceleration, 2 sec into the turn?

acen = m/sec2

528 NO

d) What is the total acceleration, 2 sec into the turn?

a = m/sec2

**2. I got parts A and B, but for part C I tried using the formula: a(cp)= rw^2, i tried using the intitial velocity, 4 m/s and also tried using the calculated velocity from part b, 8.2 and neither are being accepted, am i making a conceptual mistake here in trying to apply this formula here?**

**3. Solution attempt: a=(33)(4)^2 / 33 and also, a=(33)(8.2)^2 / 33**

I think I understand that the total will just be (At^2 + Acp^2) ^ .5 This is my first post so I hope this was in a clear enough format and not misplaced, thanks

I think I understand that the total will just be (At^2 + Acp^2) ^ .5 This is my first post so I hope this was in a clear enough format and not misplaced, thanks