Speed in still water/ throwing object horizontally.

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SUMMARY

The discussion focuses on two physics problems involving projectile motion and swimming across a river. The first problem involves a stone thrown horizontally at 10 m/s, which falls for 4.3 seconds, resulting in a cliff height of 93.145 meters, calculated using kinematic equations. The second problem addresses a swimmer crossing a 200 m wide river, taking 6 minutes and 40 seconds, while being swept 480 m downstream, leading to a swimming speed in still water of 1.5 m/s. Participants emphasize the importance of separating velocity components and applying kinematic equations correctly for accurate results.

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  • Kinematic equations for projectile motion
  • Understanding of horizontal and vertical velocity components
  • Basic principles of relative motion in fluid dynamics
  • Knowledge of unit conversions (e.g., minutes to seconds)
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Homework Statement


A stone is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. 4.3 s later the stone hits the ground. What is the height of the cliff?

A swimmer heading directly across a river 200 m wide reaches the opposite bank in 6 min 40 s. She is swept downstream 480 m. How fast can she swim in still water?

Homework Equations


The problem here is that I don't understand why some equations are used sometimes...

The Attempt at a Solution


For example, for the first question, I just calculated 43 meters, since the speed is 10 meters per second. I am aware that the speed accelerate continuously, but I don't understand which equation to use.

For the second question, it's the same thing. I found 0.5 m/s.

Thanks for explaining where I am not thinking correctly. I know that my answers are not correct (well, pretty sure)..
 
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You need to consider components of the velocities and accelerations, then apply the kinematic equations that I'm sure you know. For example, in the first case, you should split the speed [and acceleration] into two separate values, one for the vertical direction and one for the horizontal direction. Then you apply the kinematic equations to each direction separately.
 
Thanks!

But in the second question, the water is still... Do the equations still apply?...
 
future_vet said:
Thanks!

But in the second question, the water is still... Do the equations still apply?...
Not a problem!

Yes, in the second case the equations still apply. The idea behind the question is to find the component of her velocity which is perpendicular to the banks (and hence the velocity of the water), when she is swept downstream. This will be her speed in still water.
 
Thank you :)
 
future_vet said:
Thank you :)
Pleasure :smile:
 

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