(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

An 80 kg man jumps from a height of 3.00 m onto a platform mounted on springs. As the springs compress, the platform is pushed down a maximum distance of 0.200 m below its initial position, and then it rebounds. The platform and springs have negligible mass.

a. what is the man's speed at the instant the platform is depressed 0.100 m

b. if the man had just stepped gently onto the platform, how far would it have been pushed down?

2. Relevant equations

a = V/t

v = d / t

F = ma

3. The attempt at a solution

i've tried solving this one, and im stuck. heres what i did:

a = V/t

V = at

V = d/t

d/t = at

t = (d/a)^-2 = 0.553 s

V = 9.81(0.553) = 5.425 s

F = ma = 80 kg (9.81) = 62.784 kJ

and i dont know what to do next... please help me.

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# Homework Help: Speed, Kinetic Energy, Force Problem.

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