Consider a platform (mass: M) which horizontal surface AB s smoothly joined to vertical surface CD as shown in the figure below. Initially, the platform is fixed in place on a horizontal floor. A small object (mass: m) is placed on AB and given an initial speed of v in the horizontal direction so that it travels along CD, flies vertically off the platform, and reaches a maximum height of H from AB. Friction between the platform and the object is negligible. Next, the platform is kept at rest on the horizontal floor, but is no longer fixed in place. Again, the same object is placed on AB and given the same initial speed of v. The object travels along CD, floes off platform, and reaches a maximum height of from AB. Friction between the platform and the floor is negligible.
What is h/H?
K1 + U1 = K2 + U2
The Attempt at a Solution
So I got H form
½ mv^2 + 0 = 0 + mgH
H = v1^2/2g
However I'm not sure on how to get h.
I do know that some of the kinetic energy is transfered to the platform and also momentum should be conserved.