1. The problem statement, all variables and given/known data A projectile is fired with an initial speed of 68 m/s at 37 degrees above horizontal on a flat firing range. c) Determine speed of the projectile 2.3 seconds after firing. d) Determine direction of projectile 2.3 s after firing. 2. Relevant equations c) Vox=Vx=68m/s Vy=Voy*sin(theta)-gt V=sqrt(Vx^2+Vy^2) d) tan^-1(Vy/Vx)= theta 3. The attempt at a solution I got that Vx=68m/s Vy=68*sin(37)-(9.8*2.3) Vy=18.38 V=sqrt(68^2+18.4^2) V=70.4 but the velocity is not 70.4 what am I doing wrong?? Thanks for any help! The second part I get theta= 15.1 degrees but I don't want to submit it because if the first part is wrong then this is probably not right either.