- #1

user3

- 59

- 0

is it logical to ask this question in Spherical coordinates:

Using the differential length dl , find the length where r=1 0<Θ<∏/4 ∏/2< θ <∏/4 where Θ is the azimuthal angle.

What I mean by ∏/2< θ <∏/4 is that the line is a "diagonal" line which has an ascention of ∏/4 from the xy plane. I don't know how else to write it.

Is the differential length dl = sqrt( (rdΘ)^2 + (dθ)^2 ) ?

Using the differential length dl , find the length where r=1 0<Θ<∏/4 ∏/2< θ <∏/4 where Θ is the azimuthal angle.

What I mean by ∏/2< θ <∏/4 is that the line is a "diagonal" line which has an ascention of ∏/4 from the xy plane. I don't know how else to write it.

Is the differential length dl = sqrt( (rdΘ)^2 + (dθ)^2 ) ?

Last edited: