What Is the Electric Field at Various Distances From a Charged Spherical Shell?

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SUMMARY

The discussion focuses on calculating the electric field at various distances from a charged spherical shell with a uniform volume charge density of ρ = 1.63 nC/m³, an inner radius of a = 6.0 cm, and an outer radius of b = 2.70a. The electric field equations used include E = k x q/r² for points outside the shell and E = k x r(q/R³) for points inside. The calculated electric field values at specified distances (r = 1.5, r = b, r = 3b) were 18094 N/C, 82 N/C, and 1813 N/C respectively. The approach involved integrating and substituting values into the electric field equations to determine the charge enclosed.

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  • Understanding of electric fields and charge distributions
  • Familiarity with Gauss's Law and its applications
  • Knowledge of integration techniques in physics
  • Basic concepts of spherical coordinates and volume charge density
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  • Learn about the derivation and application of electric field equations for spherical shells
  • Explore integration techniques relevant to calculating electric fields
  • Investigate the effects of varying charge densities on electric fields
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Homework Statement



The figure below shows a spherical shell with uniform volume charge density ρ = 1.63 nC/m3, inner radius a = 6.0 cm, and outer radius b = 2.70a. What is the magnitude of the electric field at the following radial distances:
r=1.5, r=b, r=3b

Homework Equations



Q= sigma dV
flux = E x A
flux = charge enclosed/permittivity constant (8.85e-12)
k x q/r^2 = E (electric field outside a spherical shell of charge)

E = k x r(q/R^3) R= radius r= distance from center of shell to point where E is measured.

The Attempt at a Solution


I've tried integrating, and substituting different values of q into the Electric Field equations. I've gotten 18094, 82, and 1813 as answers. I would show my integration techniques, but it's kinda hard to do on the keyboard. haha
 
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Part I:
When r = 1.5, what's charge inside the sphere of r = 1.5 m?

When r = b or r =3b, that sphere encloses all the charge. So, Q is same but Area changes for part II and part III
 

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