Spontaneous breaking of supersymmetry

Click For Summary
SUMMARY

The discussion centers on the concept of spontaneous breaking of supersymmetry (SUSY) and the nature of the resulting Goldstone particles. It is established that due to the fermionic nature of SUSY, the Goldstone particle, referred to as a "goldstino," is a spin 1/2 fermion rather than a boson. The participants reference specific literature, including Andrea Borghese's PhD thesis and Zee's Quantum Field Theory book, to support their claims about the construction of Goldstone particles in the context of SUSY.

PREREQUISITES
  • Understanding of spontaneous symmetry breaking in quantum field theory
  • Familiarity with Goldstone's theorem
  • Knowledge of supersymmetry (SUSY) principles
  • Basic concepts of fermions and bosons in particle physics
NEXT STEPS
  • Study the construction of Goldstone particles in the context of SUSY
  • Read Andrea Borghese's PhD thesis, particularly pages 60-61 and equation (4.23)
  • Explore Zee's Quantum Field Theory, chapter 4.1, for insights on Goldstone bosons
  • Research the properties and implications of goldstinos in particle physics
USEFUL FOR

Physicists, particularly those specializing in quantum field theory and supersymmetry, as well as students seeking to deepen their understanding of Goldstone particles and their implications in theoretical physics.

shereen1
Messages
50
Reaction score
1
Dear All
I am studying spontaneous breaking of supersymmetry but i am confused about something. Why should the goldstone be a spin 1/2, why it is not a boson? I have read that this is due to supersymmetry is a fermionic symmetry but i am not convinced with this answer!
Thank you
 
Physics news on Phys.org
I'm not really into this stuff, but you should at least say why you are not convinced. See e.g. page 60-61, eqn. (4.23) of

http://thep.housing.rug.nl/sites/default/files/theses/PhD thesis_Andrea Borghese.pdf

I'd say you mimick the usual Goldstone theorem, but now for spontaneous breaking of SUSY and see how you construct the accompanying Goldstone particles. For the bosonic case, I really like Zee's treatment in his QFT book (chapter 4.1). There you can see that the Goldstone bosons are explicitly constructed using the conserved charges Q of the corresponding symmetry. In SUSY, these charges are fermionic. So I'd would be highly surprised if you wouldn't get fermionic Goldstone particles for spontaneous broken SUSY.
 
The Goldstone particle from SUSY breaking is indeed a fermion, and it's called a "goldstino". So search for "goldstino" to find more on it.
 

Similar threads

Graduate Metric Ansatz For Unifying All Forces In 11D?
  • · Replies 8 ·
Replies
8
Views
2K
Graduate Phlip Mannheim's conformal theory of everything
  • · Replies 4 ·
Replies
4
Views
3K
Graduate What does ##\delta F=0## mean?
  • · Replies 15 ·
Replies
15
Views
4K
Graduate Supertrace Sum Rule and Fermi Constant in Electroweak Standard Model
  • · Replies 4 ·
Replies
4
Views
4K
Undergrad LHC run 2, does Supersymmetry worsen hierarchy fine tuning
  • · Replies 2 ·
Replies
2
Views
2K
Graduate Twice of supersymmetric transformation = translation
  • · Replies 12 ·
Replies
12
Views
3K
Undergrad Supersymmetry breaking and hidden sector
  • · Replies 3 ·
Replies
3
Views
3K
Undergrad Spontaneous Symmetry Breaking and quantum mechanics
  • · Replies 15 ·
Replies
15
Views
2K
Graduate Stephen Adler's SU(8) theory of everything
  • · Replies 10 ·
Replies
10
Views
7K
Graduate How Do Internal Symmetry Generators Affect Supersymmetry Algebra?
  • · Replies 6 ·
Replies
6
Views
2K