Stephen Adler's SU(8) theory of everything

  • #1
1,184
349

Main Question or Discussion Point

http://arxiv.org/abs/1403.2099
SU(8) unification with boson-fermion balance
Stephen L. Adler
(Submitted on 9 Mar 2014)
We formulate an SU(8) unification model motivated by requiring that the theory should incorporate the graviton, gravitinos, and the fermions and gauge fields of the standard model, with boson--fermion balance. Gauge field SU(8) anomalies cancel between the gravitinos and spin 1/2 fermions. The 56 of scalars breaks SU(8) to SU(3)family×SU(5)/Z5, with the fermion representation content needed for ``flipped'' SU(5), and with the residual scalars in the representations needed for further gauge symmetry breaking to the standard model. Yukawa couplings of the 56 scalars to the fermions are forbidden by chiral and gauge symmetries. In the limit of vanishing gauge coupling, there are N=1 and N=8 supersymmetries relating the scalars to the fermions, which restrict the form of scalar self-couplings and should improve the convergence of perturbation theory, if not making the theory finite and ``calculable''. In an Appendix we give an analysis of symmetry breaking by a Higgs component, such as the (1,1)(−15) of the SU(8) 56 under SU(8)⊃SU(3)×SU(5)×U(1), which has nonzero U(1) generator.

This is an odd but interesting paper - an attempt to describe a field-based theory-of-everything that resembles N=8 supergravity but which isn't actually supersymmetric. As in supersymmetry, the number of bosonic and fermionic degrees of freedom is the same, and the nongravitational part of the theory has some supersymmetries in the limit of zero coupling.

Back before the 1984 superstring revolution, when supergravity was the hottest unification theory available, there were some attempts to find the standard model inside N=8 supergravity that were ingenious but strained. This theory of Adler's comes from the other direction - he takes a common GUT framework (plus gravitinos) and then bends it to look like an N=8 supermultiplet. Those of us who have attempted something similar, should see if Adler is onto something.
 
Last edited:

Answers and Replies

  • #2
marcus
Science Advisor
Gold Member
Dearly Missed
24,738
785
Last edited:
  • #3
atyy
Science Advisor
13,906
2,175
Adler, with Bell and Jackiw, is a co-discoverer of the axial anomaly.
 
  • #4
arivero
Gold Member
3,304
59
Adler, with Bell and Jackiw, is a co-discoverer of the axial anomaly.
Indeed. And still, a bit of outsider, because of the quaternionic thing. I like the mix.
 
  • #5
PAllen
Science Advisor
2019 Award
8,095
1,381
He was also a pioneer in the current algebras before the standard model came to be, especially the Adler sum rules. Incredibly prolific: well over 100 serious papers in arxiv since 1994, which represents substantially less than half his career! (I've been a 'fan' for a long time).

A summary of his work:

http://arxiv.org/abs/hep-ph?papernum=0505177/
 
  • #6
Berlin
Gold Member
57
2
Could Adler's paper renew interest in E(8) unification? Something like E(8) > E(7) x SU(2) > SU(8) x SU(2). Could Adler's particle content and LQG together fit into E(8)? Crazy thoughts. Surely, the weak limit linear gravity is a weak point of his scheme. In the paper he suggests that searching for a bigger group is his next step.... Hopefully Jacques Distler steps in to fill in the details :)

Berlin

NB I do not think that Adler sees his paper as a ToE. The title of this thread could better use the phrase Unification in the sense as for EW unification, a step but not the last.
 
Last edited:
  • #7
984
174
I used my Lie-algebra code on this proposed GUT model, and I found:

SU(8) -> SU(5)*SU(3)*U(1)

Adjoint:
63 = (24,1,0) + (1,8,0) + (0,0,0) + (5,3*,1) + (5*,3,-1)
Antisymmetric tensors:
1 = (1,1,0)
8 = (5,1,3/8) + (1,3,-5/8)
28 = (5,3,-1/4) + (10,1,3/4) + (1,3*,-5/4)
56 = (5,3*,-7/8) + (10,3,1/8) + (10*,1,9/8) + (1,1,-15/8)
70 = (5,1,-3/2) + (10,3*,-1/2) + (10*,3,1/2) + (5*,1,3/2)
56* = (10,1,-9/8) + (10*,3*,-1/8) + (5*,3,7/8) + (1,1,15/8)
28* = (10*,1,-3/4) + (5*,3*,1/4) + (1,3,5/4)
8* = (5*,1,-3/8) + (1,3*,5/8)
1' = (1,1,0)

Let's see what can give the Georgi-Glashow model:
SU(5) -> SU(3)*SU(2)*U(1)

SU(5) mass terms (left-handed):
Up: F(10).F(10).H(5)
Neutrino: F(5*).F(1).H(5)
Down, electron: F(10).F(5*).H(5*)
MSSM Higgs mu: H(5).H(5*)
RH nu Maj mass: F(1).F(1)

F = elementary fermion (3 generations), H = Higgs particle (1 generation? 3 generations?)

I find lots of possibilities for some of those mass terms.
 
  • #8
984
174
At first sight, these antisymmetric-tensor irreps suggest this superalgebra: SO(16)

SO(16) -> SU(8) * U(1)

This connects to E8:
E8 -> SO(16)
248 -> 120 (adjoint) + 128 (one of the two spinors, which are each self-dual)

A problem with SO(16) -> SU(8), however:
One spinor -> 1 + 28 + 70 + 28* + 1'
The other spinor -> 8 + 56 + 56* + 8*

So it does not fit as well with chirality, because all these irreps share chirality. One doesn't have an important feature of the Standard Model, SU(5), SO(10), and E6, where one gets EF rep duality fitting in with EF reversed chirality.

Let's try E8 -> E7 * SU(2)
248 -> (133,1) + (1,3) + (56,2)
Adjoint, scalar, fundamental

Now E7 -> SU(8)
56 -> 28 + 28*
AS 2-tensor and its dual
133 -> 63 + 70
Adjoint, AS 4-tensor
 
  • Like
Likes arivero
  • #9
984
174
I tried finding SU(8) versions of the SU(5) mass terms, but I could not get sensible results.

Adler's field content:

Graviton: spin = 2, rep = 1 (scalar), hel = 2
Vector-spinor: spin = Weyl 3/2, rep = 8 (vector) for L, hel = 16
Vector: spin = 1, rep 63 (adjoint), hel = 126
Spinor: spin = Weyl 1/2, rep = 56 (AS 3-tensor) for L, hel = 112
Boson, fermion hel = 128

Spinor (two of them): spin = Weyl 1/2, rep = 28* (dual AS 2-tensor) for L, hel = 112
Scalar (complex): spin = 0, rep = 56 (AS 3-tensor), hel = 112
Boson, fermion hel = 112

hel = number of helicity states, rep = representation, L = left-handed chirality

There aren't any sensible interaction terms with 2 or 3 spinor particles. For 4 of them, they'd all have rep 28*. A rep 56 is equivalent to two rep 28* particles here, so for 5 particles, 3 would be 28*'s, and 2 would be 56's.

So to get to a more typical GUT like Georgi-Glashow or flipped SU(5), one would need some complicated symmetry breaking. It would need to produce the mass matrices, which completely break the SU(3) generation symmetry of this model.
 
  • #10
Berlin
Gold Member
57
2
New version of Adlers paper appeared. Happy to see his added hint about E(8). A faint proof that he actually reads this forum :)

berlin
 
  • #11
stevendaryl
Staff Emeritus
Science Advisor
Insights Author
8,401
2,580
This is an odd but interesting paper - an attempt to describe a field-based theory-of-everything that resembles N=8 supergravity but which isn't actually supersymmetric.
If it's not supersymmetric, then what's the motivation for including a gravitino? Isn't that just hypothesized as the supersymmetric partner of the graviton?
 

Related Threads on Stephen Adler's SU(8) theory of everything

  • Last Post
Replies
8
Views
3K
Replies
31
Views
3K
  • Last Post
2
Replies
29
Views
4K
Replies
31
Views
5K
  • Last Post
Replies
7
Views
6K
  • Last Post
Replies
4
Views
3K
  • Last Post
2
Replies
48
Views
11K
  • Last Post
Replies
4
Views
2K
Replies
6
Views
2K
  • Last Post
2
Replies
26
Views
3K
Top