Spring constant of Achilles tendon

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SUMMARY

The spring constant of the Achilles tendon can be calculated using the formula k = ΔF/Δx, where ΔF is the change in force and Δx is the change in length. In this case, the tendon stretches 0.51 cm (0.0051 m) under a force increase from 3400 N to 5800 N, resulting in a spring constant of k = (5800 N - 3400 N) / 0.0051 m, which equals approximately 470,588 N/m. Additionally, the work done by the muscle in stretching the tendon can be calculated using the work formula W = (1/2) * k * Δx², which requires the correct spring constant value for accurate results.

PREREQUISITES
  • Understanding of Hooke's Law (Fx = -kx)
  • Familiarity with basic physics concepts such as force and work
  • Knowledge of unit conversions (e.g., cm to m)
  • Ability to perform calculations involving linear relationships
NEXT STEPS
  • Calculate the spring constant of other biological tendons using similar methods
  • Explore the implications of tendon elasticity on athletic performance
  • Learn about the biomechanics of muscle-tendon interactions
  • Investigate advanced applications of Hooke's Law in engineering
USEFUL FOR

Students studying biomechanics, physiotherapists analyzing tendon properties, and sports scientists researching muscle performance and injury prevention.

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Homework Statement


(a) If the length of the Achilles tendon increases 0.51 cm when the force exerted on it by the muscle increases from 3400 N to 5800 N, what is the "spring constant" of the tendon?
1Your answer is incorrect.
(b) How much work is done by the muscle in stretching the tendon 0.51 cm as the force increases from 3400 N to 5800 N?


Homework Equations


Fx=-kx
k=f1/x1


The Attempt at a Solution


I'm stuck on part a, I used k=f1/x1=(3400/0.51) to find the spring constant but got the wrong answer.
 
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Check your units.

.51 cm = .0051 m

Also

ΔF = -kΔx
 
Do you know by how much the spring elongated under the effect of 3400N, or under the effect of 5800N, or do you only know the difference between the two elongations?
Remember that the ratio between the elongation of an ideal spring and the force exerted on it is linear.
 

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