- #1

Perander

- 8

- 1

- Homework Statement
- We have the task of calculating the spring constant in two ways. One way is to use the formula F = kx (1) and the other formula to use the formula for the oscillation time of a harmonic motion T=2pi*sqrt(m/k) = T^2 = (2pi)^2/k * m (2). And then we will answer the following questions:

1. Were the values of spring constant equal when using two ways calculating it?

2. What value should be used, i.e. the value in formula 1 or 2?

3. Can you analyze errors in measurements and calculation methods to arrive at which of the methods in formula 1 or 2 is better?

- Relevant Equations
- 1. F = k*x

2. T ^ 2 = (2pi) ^ 2 / k * m.

T ^ 2 = K * m

In question 1, the spring constant from the two formulas was not the same. When we used the first formula, we got that the spring constant was 7.83 N / m. The second formula we got that the spring constant was 8,03 N / m.

In questions 2 and 3 I do not know and am unsure about how to answer. Using the first formula F=k*x, we found that the spring constant is equal to the force divided by the spring elongation in meters. . Using the second formula, we obtained that T ^ 2 = K * m (where K corresponds to the gradient of the graph) and T ^ 2 = (2pi) ^ 2 / k * m.

K * m = (2pi) ^ 2 / k * m and from that you can get small k (the spring constant).

In questions 2 and 3 I do not know and am unsure about how to answer. Using the first formula F=k*x, we found that the spring constant is equal to the force divided by the spring elongation in meters. . Using the second formula, we obtained that T ^ 2 = K * m (where K corresponds to the gradient of the graph) and T ^ 2 = (2pi) ^ 2 / k * m.

K * m = (2pi) ^ 2 / k * m and from that you can get small k (the spring constant).

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