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Spring force with free fall problem

  1. Jan 30, 2012 #1
    1. The problem statement, all variables and given/known data

    Consider the system below. The 2.50 kg mass compresses the spring (k = 805 N/m) a distance of 0.230 m from equilibrium. The mass is then released from rest. It slides a total distance of 1.20 m on the table top where it feels a force of kinetic friction of 5.60 N before it slides off the edge. If it hits the ground with a speed of 6.64 m/s, find the height ∆y of the table.

    2. Relevant equations

    Vf^2 = Vi^2-2g∆y


    3. The attempt at a solution

    I started doing the spring force part of the problem, but then the thought hit me that the speed shouldn't matter in the x direction because it is just a free fall problem. I'm not sure if I'm correct in that thinking though.

    here's what I got.

    ∆y = (Vf^2 - Vi^2)/-2g

    ∆y = (6.64^2 - 0^2)/-2(9.81)

    ∆y = 44.0896/-19.62

    ∆y = 2.25m
     
  2. jcsd
  3. Jan 30, 2012 #2

    PeterO

    User Avatar
    Homework Helper


    It is not a simple free fall problem.

    If the mass just tipped over the edge, it just falls to the floor reaching a speed of 6.64

    If however the mass leaves the table travelling at a speed of 6.6 m/s, it will have gained the extra 0.04 m/s by falling just a few mm.

    In the end this is a projectile motion question: you have to work out how fast the mass is travelling when it leaves the table.
     
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