A horizontal spring with a constant of 700N/m is compressed 2cm. A ball of mass 200g is placed in front of the spring. The spring is released. The ball slides along a horizontal track for 10cm while experiencing a frictional force of 0.75N. What is the velocity of the ball at the 10cm mark?
- PEs= .5⋅Kx^2
- .5⋅Kxi^2 + .5⋅m⋅Vi + mg⋅yi + Fnc⋅Δd= .5⋅Kxf^2 + mg⋅yf
3. The Attempt at a Solution
We just started learning about this in class the other day. Im not sure if the second equation is correct... but i know that the y-direction isnt included in this problem. K is the spring constant but I'm not sure what x is (Kx or Kxi)
If Kx is spring force do i multiply 700n/m and 0.75N? Im not really sure where to start here or which equation to use to find the velocity