Spring-Mass system with friction

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SUMMARY

The discussion focuses on a Spring-Mass system subjected to a constant friction force, analyzing the amplitude decay during oscillations. The amplitude decreases by a fixed amount of 2f/k with each cycle, as derived from the conservation of energy principles. The total distance the mass travels before coming to rest is calculated using the relationship between initial amplitude and friction force, leading to the equation x = nx0 - (2f/k)(1 + 2 + ... + n - 1). The confusion arises from the definition of a complete cycle, which is clarified as the mass returning to the same side of the equilibrium point.

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Homework Statement


A block shown in the drawing is acted on by a spring with spring constant k, and a weak friction force of constant magnitude f . The block is pulled distance x0 from equilibrium and released. It oscillates many times before coming to a halt.

(a) Show that the amplitude decreases by same amount in each cycle of oscillation.

(b) Find the number of cycles n, the mass oscillates before coming to rest.

Homework Equations


Conservation of energy

The Attempt at a Solution


For (a) I used conservation of energy. Let xi be the amplitude of a cycle (with energy Ei) and xf be the amplitude (with energy Ef)

[itex]E_{i}=\frac{1}{2}kx_{i}^{2}[/itex]
[itex]E_{f}=\frac{1}{2}kx_{f}^{2}+f(x_{o}+x_{f})[/itex]

Yielding

[itex]x_{f}=x_{i}-\frac{2f}{k}[/itex]

Showing that the amplitude decreases by 2f/k between subsequent cycles.

For (b) I calculated the distance x for the mass to come to rest at:

[itex]\frac{1}{2}kx_{o}^{2}=fx \implies x=\frac{kx_{o}^{2}}{2f}[/itex]

Meanwhile, the total distance covered by the block using the result from (a),

[itex]x=x_{0}+x_{0}-\frac{2f}{k}+x_{0}-\frac{4f}{k}+(...)+x_{0}-\frac{2(n-1)f}{k}[/itex]

for n cycles. Simplifying,

[itex]x=nx_{0}-\frac{2f}{k}(1+2+(...)+n-1)[/itex]

If I equate those expressions, I don't get the right answer. Any hints?
 
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It looks like your "initial" and "final" energies are not a whole cycle but only half a cycle apart. Can you see why?
 
So a cycle is when the mass returns to the same side? If that is so, I can't see how talking about amplitude makes any sense, as the mass does not even go x0 on the other side of the equilibrium point, but rather goes [itex]x_{0}-\frac{2f}{k}[/itex] as I showed.
 

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