- #1

san12345

- 5

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- Homework Statement
- a ball of mass 0.1 Kg is dropped on a spring. Spring gets compressed by 0.1 m. After releasing, How far will ball go upward ? ( g= 9.8 )

I tried following step. Please someone explain me if i am correct or not

Spring Constant K = f/x = 0.1 * 9.8 / 0.1 = 9.8

K=9.8

And then i get confused. i assume potential energy of ball is mgh which gets converted to (1/2)kx^2 which is potential energy of spring. But (1/2)kx^2 gets converted to kinetic energy (1/2)mv^2. And when ball reaches up it has again potential energy. So (1/2)mv^2 = mgh ?

So mgh = (1/2)kx^2 = (1/2)mv^2 but it gives wrong answer.

Please someone explain me equations of PE and KE before and after compression of spring.

- Relevant Equations
- mgh = (1/2)kx^2

(1/2)kx^2 = (1/2)mv^2

please help me