Spring question, how do I know it is negative or positive?

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Homework Help Overview

The discussion revolves around the interpretation of displacement and compression in the context of a spring problem. Participants are examining why the initial compression, denoted as x0, is considered positive and the implications of this choice in relation to the spring's equilibrium position.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the sign convention for displacement and compression, particularly whether x0 should be treated as positive or negative. Some are exploring the definitions of distance versus displacement in this context.

Discussion Status

The conversation is ongoing, with participants providing insights into the definitions of compression and displacement. There are differing views on the implications of sign conventions and how they relate to the physical setup of the problem.

Contextual Notes

There is a focus on the language used in the problem statement and how it influences the interpretation of the spring's behavior. Participants are considering the conventional directions for positive and negative displacements in relation to the spring's equilibrium position.

flyingpig
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Homework Statement




[PLAIN]http://img33.imageshack.us/img33/8751/49753333t.jpg

Problem #2

[PLAIN]http://img121.imageshack.us/img121/5574/35712633.jpg

My question is, why do they take positive x0? Shouldn't it be negative since it is that amount of x displacement away from the spring?
 
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flyingpig said:
My question is, why do they take positive x0? Shouldn't it be negative since it is that amount of x displacement away from the spring?
No, x0 is the distance the spring is compressed.
 
Doc Al said:
No, x0 is the distance the spring is compressed.

Distance? But why?
 
flyingpig said:
Distance? But why?
Read the problem statement ("...the initial compression x0...") and look at the diagram.

What would a negative compression mean? A stretching?

If they asked "What is the initial displacement of the spring from its equilibrium position taking 'to the right' as positive?" then you'd give a negative answer.
 
Doc Al said:
Read the problem statement ("...the initial compression x0...") and look at the diagram.

What would a negative compression mean? A stretching?

If they asked "What is the initial displacement of the spring from its equilibrium position taking 'to the right' as positive?" then you'd give a negative answer.

But the "Initial compression x0 doesn't really say it is distance or displacement and I thought x in (1/2)kx^2 is always displacement

Also, isn't it always generally taken the right side as the positive and the left side (away from the equilibrium position) is always negative?

Also, even if it is asking for the displacement, what if you take the absolute value? Wouldn't they both work since at the end you will be squaring it again.
 
flyingpig said:
But the "Initial compression x0 doesn't really say it is distance or displacement
This is more of an English question than a physics question. Seems clear enough to me that "compression" would be a positive number.
and I thought x in (1/2)kx^2 is always displacement
Sure. So?

Also, isn't it always generally taken the right side as the positive and the left side (away from the equilibrium position) is always negative?
If you were asked for the displacement, then that would be the typical convention.

Also, even if it is asking for the displacement, what if you take the absolute value?
I thought you just stated that if they asked for the displacement, the answer would be negative. Taking the absolute value would give you the wrong answer.
Wouldn't they both work since at the end you will be squaring it again.
The value of the spring potential energy is independent of the sign of the displacement. But that doesn't mean that the sign of the displacement makes no difference. (If the displacement were positive--using your convention--that means that the spring was stretched to the right, which would not make sense for this problem.)
 

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