- #1
supernova1203
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Homework Statement
A spring toy is launched from the ground at 2.3 m/s at an angle of 78 degrees to the ground. What is the maximum height reached by the spring toy?
Homework Equations
At first i thought it was asking us to find displacement, i realized later total displacement would be 0, since it eventually comes back down, so i thought, hey theyre just asking us to find max vertical distance right?
so instead of using the following formula to find displacement(I still use it to find time)
Δdv=VvΔt+1/2aΔt^2
I decided to go with d=vt
and i used Vv=v1sin∅
The Attempt at a Solution
Vv=v1sin∅
=2.3sin78
Vv=2.24m/s
then i use this into displacement formula and solve for time.
Δdv=VvΔt+1/2aΔt^2
=2.2Δt+1/2aΔt^2
=2.2Δt+1/2(-9.8)Δt^2
=2.2Δt+(-4.9)Δt^2 (here we factor out Δt)
and we are left with
=2.2+(-4.9)Δt
4.9Δt=2.2
Δt=2.2/4.9
Δt=0.4s
now that we have both time and vertical velocity we can find max distance.
d=vt
=(2.24)(0.4)
d=0.896m
does it look right?