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## Homework Statement

A daredevil motorcyclist attempts to leap a 48m wide gorge. At the side where the cyclist starts, the ground slopes upward at an angle of 15 degrees. Beyond the far rim, the ground is level and is 5.9m below the near rim. what is the minimum speed necessary for the cyclist to clear the gorge?

## Homework Equations

Kinematics Equations

s=d/t

d= vf(t)-0.5(a)(t)2

## The Attempt at a Solution

First I just used Pythagorean therm to find Δd. 48

^{2}+5.9

^{2}= c

^{2}

c= 48.36

Used equation to find time

Δd = V

_{f}Δt-0.5(a)Δt

^{2}

48.36= -0.5(-9.8)Δt

^{2}

48.36 = 4.9Δt

^{2}

48.36/4.9=Δt

^{2}

9.86 =Δt

^{2}

+ - 3.14 = Δt

s=d/t

s=48.36/3.14

s=15.4 m/s

I think I was suppose to do something with 15 degrees.

I got the answer as 15 m/s, but I believe its wrong.

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