Spring with 2 forces at both end

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SUMMARY

The discussion centers on the application of Hooke's Law to two scenarios involving springs. In the first scenario, a light spring with a spring constant of 639.4667 N/m is stretched from 33.0 cm to 46.50 cm by an 8.80 kg mass. The second scenario involves two individuals pulling on a spring with a force of 170 N each, leading to confusion regarding the effective force applied. The correct interpretation reveals that only one of the forces contributes to the spring's extension due to the fixed end, emphasizing the importance of understanding force equilibrium in static systems.

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  • Understanding of Hooke's Law and spring constants
  • Basic knowledge of force equilibrium and Newton's laws
  • Familiarity with concepts of mass, weight, and gravitational force
  • Ability to perform calculations involving force, mass, and acceleration
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  • Study the implications of Hooke's Law in dynamic systems
  • Learn about force equilibrium in static and dynamic scenarios
  • Explore the effects of friction on spring systems and block motion
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of Hooke's Law applications in real-world scenarios.

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Homework Statement


Hooke's law describes a certain light spring of unstressed length 33.0 cm. When one end is attached to the top of a door frame and a 8.80 kg object is hung from the other end, the length of the spring is 46.50 cm.
(a) Find its spring constant. (639.4667N/m)
(b) The load and the spring are taken down. Two people pull in opposite directions on the ends of the spring, each with a force of 170 N. Find the length of the spring in this situation.

The Attempt at a Solution



For the part B, the spring with two 170N at both end should be equal to 340N at one end and the other end fixed.

since the K = 639.4667N/m
F=kx
340 = (639.4667)x
x = 0.531m

then the total length should be 0.33m + 0.531m isn't?
but my answer is wrong =(

Homework Statement


A light spring with force constant 3.25 N/m is compressed by 5.00 cm as it is held between a 0.300 kg block on the left and a 0.600 kg block on the right, both resting on a horizontal surface. The spring exerts a force on each block, tending to push them apart. The blocks are simultaneously released from rest. Find the acceleration with which each block starts to move, given that the coefficient of kinetic friction between each block and the surface is the following values. Let the coordinate system be positive to the right and negative to the left.

The Attempt at a Solution


I don't understand why we could assume the spring forces apply on both blocks are equally the same?
 
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For the part B, the spring with two 170N at both end should be equal to 340N at one end and the other end fixed.
This seems sensible, but it is not. Consider part (a) again. Gravity pulls down on the mass and spring with 86 N. But the spring does not accelerate according to F = ma. Something must be holding it up and cancelling out the 86 N force, because the acceleration is zero. The spring is attached to a door frame, and that door frame is holding it up with a force of 86 N upward.

The same holding force is acting in (b). One of the 340 N forces is just preventing the spring from accelerating away. Only the other 340 N counts in the F = kx formula.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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