1. The problem statement, all variables and given/known data A 0.50-kg mass is attached to a spring of spring constant 20 N/m along a horizontal, frictionless surface. The object oscillates in simple harmonic motion and has a speed of 1.5 m/s at the equilibrium position. (a) What is the amplitude of vibration? I already solved for the amplitude and got 0.24 meters. (b) At what location are the kinetic energy and the potential energy the same? ??? 2. Relevant equations E = 1/2mv^2 + 1/2kx^2 3. The attempt at a solution E = 1/2mv^2 + 1/2kx^2 I thought I would set the kinetic energy and potential energy equal to each other, so I got: 1/2(.5)(1.5)^2 = 1/2(20)x^2 From that, I got x = .24 meters. But that's wrong and the answer is 0.17 meters. I'm confused as to where I went wrong. :( Thank you!!