- #1
Carrie
- 27
- 0
Homework Statement
A 0.50-kg mass is attached to a spring of spring constant 20 N/m along a horizontal, frictionless surface. The object oscillates in simple harmonic motion and has a speed of 1.5 m/s at the equilibrium position.
(a) What is the amplitude of vibration?
I already solved for the amplitude and got 0.24 meters.
(b) At what location are the kinetic energy and the potential energy the same?
?
Homework Equations
E = 1/2mv^2 + 1/2kx^2
The Attempt at a Solution
E = 1/2mv^2 + 1/2kx^2
I thought I would set the kinetic energy and potential energy equal to each other, so I got:
1/2(.5)(1.5)^2 = 1/2(20)x^2
From that, I got x = .24 meters.
But that's wrong and the answer is 0.17 meters. I'm confused as to where I went wrong. :(
Thank you!