- #1
pataflora said:The value of x that makes V’ = 0 is 10 and 10/3
- - - Updated - - -
Would that be a minimum or a maximum?
pataflora said:I have researched the topic. So x = 10/3 will be substituted into the derivative equation, giving a result of 0
The "Square Sheet of Cardboard Problem" is a mathematical puzzle that involves cutting a square piece of cardboard into smaller squares with no leftover pieces. It is also known as the "Square Peg Problem" or the "Square Dissection Problem".
The "Square Sheet of Cardboard Problem" was first proposed by renowned mathematician David Hilbert in 1902. He challenged his students to find a solution to the problem, but it was not until 1939 that a complete solution was found by mathematician Henry Dudeney.
The solution to the "Square Sheet of Cardboard Problem" is to cut the original square into smaller squares with side lengths of 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, and 12 units. This creates a total of 12 squares with no leftover pieces.
Yes, there are infinitely many solutions to the "Square Sheet of Cardboard Problem". As long as the smaller squares have side lengths that are consecutive integers, the puzzle can be solved. However, the solution with 12 squares is considered the most elegant and efficient.
The "Square Sheet of Cardboard Problem" is a classic example of a mathematical puzzle that challenges critical thinking and problem-solving skills. It also has applications in geometry and can be used to teach concepts such as area and perimeter. Additionally, the problem has sparked interest and research in the field of combinatorics and has led to the discovery of other similar puzzles.