Squaring of vectors in absolute value

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SUMMARY

The discussion clarifies that the expression |\vec{a}+\vec{b}|^{2} is equivalent to (\vec{a}+\vec{b})^{2} when the multiplication is defined as the dot product. The magnitude of the vector sum, represented as √(a^{2}+b^{2}), specifically applies when \vec{a} and \vec{b} are orthogonal vectors. This relationship emphasizes the importance of understanding vector operations in linear algebra.

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  • Understanding of vector operations, specifically dot product and magnitude.
  • Familiarity with linear algebra concepts, including orthogonal vectors.
  • Knowledge of mathematical notation for vectors and their properties.
  • Basic skills in manipulating algebraic expressions involving vectors.
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  • Learn about orthogonal vectors and their significance in geometry.
  • Explore vector magnitude calculations and their applications.
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M. next
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Is |\vec{a}+\vec{b}|^{2} equal to the same thing as (\vec{a}+\vec{b})^{2}? And when is it equal to √(a^{2}+b^{2})?

Thanks.
 
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M. next said:
Is |\vec{a}+\vec{b}|^{2} equal to the same thing as (\vec{a}+\vec{b})^{2}?
They're the same, assuming the implied multiplication in the expression on the right is the dot product. Otherwise, multiplication of one vector by another is not defined (with the exception of the cross product).
M. next said:
And when is it equal to √(a^{2}+b^{2})?

Tip: You don't need so many tex or itex tags. Your squared vector sum can be written like this:
[itex[/color]](\vec{a} +\vec{b})^2 [/itex]
Or instead of the itex tags, you can use ## delimiters at the front and back.
 
Thank you for the reply and the tip. But about the √(a^2+b^2)?? My second part of the question?
 
M. next said:
Thank you for the reply and the tip. But about the √(a^2+b^2)?? My second part of the question?

That is merely the magnitude of both vectors. Assuming that's what you mean? You were a little unclear on the second part. Think of magnitude as the size or length of those two vectors.
 
M. next said:
Thank you for the reply and the tip. But about the √(a^2+b^2)?? My second part of the question?

\sqrt{a^2+b^2} is the magnitude of \vec{a}±\vec{b},where \vec{a} and \vec{b} are orthogonal (perpendicular) vectors.
 
Okay. Thank you, yes, it is exactly what I meant.
 

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