Geometrical meaning of magnitude of vector product

In summary, the geometrical meaning of $$|\vec v \times \vec w | $$ is the area of the parallelogram formed by the two vectors as adjacent sides. It is related to the perpendicular distance from point ##V## to the line passing through ##O## and ##W##, but also involves the magnitude of ##\vec{OW}##. The cross product is a (pseudo)vector and its magnitude is of dimension L, not L^2 as for the area. One can also use the unit vector \hat w along the line ##OW## to find the distance from that line to point ##V##.
  • #1
songoku
2,426
363
TL;DR Summary
I have notes that tells me one of the geometrical meaning of magnitude of vector product is related to perpendicular distance. Please see the diagram below
1629344653128.png


My notes says that the geometrical meaning of $$|\vec v \times \vec w | $$ is the perpendicular distance from point ##V## to line passing through ##O## and ##W## (all vectors are position vectors)

$$|\vec v \times \vec w | = |\vec v| |\vec w| \sin \theta$$

From the picture, the perpendicular distance is ##|\vec v| \sin \theta ## but from the equation, there is extra ##|\vec w|## so it seems to me that the geometrical meaning is not the perpendicular distance but more like the multiplication of perpendicular distance from point ##V## to line ##OW## and magnitude of ##\vec{OW}##

Am I misunderstood something?

Thanks
 
Mathematics news on Phys.org
  • #2
The magnitude of v x w is the area of the parallelogram. It's "related to" the height in the sense that the area is the height multiplied by |w|.
 
  • Like
Likes songoku
  • #3
mfb said:
The magnitude of v x w is the area of the parallelogram. It's "related to" the height in the sense that the area is the height multiplied by |w|.
I understand the other geometrical meaning is area of parallelogram but is it correct to say that one of the geometrical meaning is (only) perpendicular distance from a point to a line (without stating there is multiplication with magnitude of the line) ?

Because if I am asked to find perpendicular distance from ##V## to line ##OW##, I would calculate ##|\vec v| \sin \theta##, not ##|\vec v| |\vec w| \sin \theta##

Thanks
 
  • #4
songoku said:
more like the multiplication of perpendicular distance from point ##V## to line ##OW## and magnitude of ##\vec{OW}##

Am I misunderstood something?
You are correct. Your notes must have missed something.
 
  • Like
Likes songoku
  • #5
Thank you very much mfb and FactChecker
 
  • #6
So the magnitude of the cross product is the area of the parallelogram with the two vectors as adjacent sides.
 
  • Like
Likes songoku
  • #9
FactChecker said:
So the magnitude of the cross product is the area of the parallelogram with the two vectors as adjacent sides.
And what is interesting: the cross product is a (pseudo)vector and its magnitude should be of dimension L but not L^2 as it is so for the area :)
 
  • #10
songoku said:
I understand the other geometrical meaning is area of parallelogram but is it correct to say that one of the geometrical meaning is (only) perpendicular distance from a point to a line (without stating there is multiplication with magnitude of the line) ?

Because if I am asked to find perpendicular distance from ##V## to line ##OW##, I would calculate ##|\vec v| \sin \theta##, not ##|\vec v| |\vec w| \sin \theta##

Thanks
Use the unit vector [itex]\hat w[/itex] along the line ##OW##.
(Indeed, what role would the length of the segment ##OW## play
to find the distance from that line to point ##V##?)
 
Back
Top