I General equation for the magnitude of the difference vector

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Summary
General equation for the magnitude of the difference vector of two parallel or antiparallel vectors
Hi everyone,

While finding the solution for one of my exercises, I found the following answer. I'm seriously questioning if the equations provided in that answer are reversed. According to my understanding, if two vectors ##\vec{S}## and ##\vec{T}## are parallel (same direction) the magnitude of the difference vector ##\vec{S}-\vec{T}## is:

$$
||\vec{S}| - |\vec{T}||
$$

If the vectors are antiparallel, the magnitude of the difference vector is:
$$
|\vec{S}| + |\vec{T}|
$$

Did the author of that answer wrote the equations in the wrong places or am I missing something?

Thanks.
 

phinds

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Sure looks to me like you have it right and he has it reversed from what it should be.
 
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Thanks for the confirmation, phinds.
 

Stephen Tashi

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If the vectors are antiparallel, the magnitude of the difference vector is:
$$
|\vec{S}| + |\vec{T}|
$$
For example, in 2D, let ## \vec{S} = \overrightarrow{(1,0)}## and let ##\vec{T} = (-1)(\vec{S}) = \overrightarrow{(-1,0)}##

## \overrightarrow{S-T} = \overrightarrow{(1,0)} - \overrightarrow{(-1,0)} = \overrightarrow{ (2,0)}##.
 

PeroK

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Summary: General equation for the magnitude of the difference vector of two parallel or antiparallel vectors

Hi everyone,

While finding the solution for one of my exercises, I found the following answer. I'm seriously questioning if the equations provided in that answer are reversed. According to my understanding, if two vectors ##\vec{S}## and ##\vec{T}## are parallel (same direction) the magnitude of the difference vector ##\vec{S}-\vec{T}## is:

$$
||\vec{S}| - |\vec{T}||
$$

If the vectors are antiparallel, the magnitude of the difference vector is:
$$
|\vec{S}| + |\vec{T}|
$$

Did the author of that answer wrote the equations in the wrong places or am I missing something?

Thanks.
You could try an example where ##\vec{T} = \vec{S}## (parallel) and ##\vec{T} = - \vec{S}## (anti-parallel).
 
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Hi Perok, thanks for replying.

I tried already with a few cases and I'm kind of sure that the author got the equations reversed. I'm asking mostly for confirmation.
 

PeroK

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Hi Perok, thanks for replying.

I tried already with a few cases and I'm kind of sure that the author got the equations reversed. I'm asking mostly for confirmation.
When you say "author", it would help if you said who you were talking about. The page you linked to seemed to be saying what you are saying.
 

Stephen Tashi

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I tried already with a few cases and I'm kind of sure that the author got the equations reversed.
You're doing something wrong.
 

PeroK

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PeroK

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if two vectors ##\vec{S}## and ##\vec{T}## are parallel (same direction) the magnitude of the difference vector ##\vec{S}-\vec{T}## is:

$$
||\vec{S}| - |\vec{T}||
$$

If the vectors are antiparallel, the magnitude of the difference vector is:
$$
|\vec{S}| + |\vec{T}|
$$
Just to be clear. Are you saying this is right or wrong?
 
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4
I'm saying that the author of this answer, got the equations in the wrong places. And what I wrote in my post is what it should be.
 

PeroK

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I'm saying that the author of this answer, got the equations in the wrong places. And what I wrote in my post is what it should be.
They look the same to me!
 
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Oh, indeed, they are the same now. It seems that the edition request has been approved.
 

Stephen Tashi

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They look the same to me!
Me too. To be specific, the formulae in the original post look the same as the formulae given in answer 1 on the stackexchange page.

Answer 1 on https://physics.stackexchange.com/questions/304634/what-is-the-magnitude-of-the-difference-vector/304644#304644 :

The magnitude of the difference vectors depends on the orientation of S⃗ and T⃗ . If they are parallel then |S⃗ −T⃗ |=||S⃗ |−|T⃗ || and if they are anti-parallel then |S⃗ −T⃗ |=|S⃗ |+|T⃗ |.
Can answers on stackexchange be edited?
 

PeroK

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Sorry for the confusion guys. I saw that that answer was wrong, asked here for confirmation on my alternative, and, after that, I edited the answer in Stack Overflow.

And, yes! Thankfully, answers in StackExchange can be improved/edited.
 
Last edited:

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