Stacked blocks on an accelerating elevator

Click For Summary

Homework Help Overview

The problem involves four blocks of varying masses stacked in an elevator that is accelerating downward. The objective is to determine the contact force between two specific blocks, the 30kg and 40kg masses, while considering the effects of the elevator's acceleration on the forces acting on the blocks.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of Newton's second law to calculate forces acting on the blocks. There is an exploration of how the acceleration of the elevator affects the perceived weight of the blocks, with questions about whether the blocks feel heavier or lighter during downward acceleration.

Discussion Status

Some participants have provided calculations and reasoning regarding the contact force, while others have questioned the assumptions made in the calculations. There is a recognition of differing interpretations of the forces involved, and some guidance has been offered regarding the correct approach to determining the contact force.

Contextual Notes

Participants are considering the implications of the elevator's acceleration being equal to gravitational acceleration, as well as the effects of different acceleration values on the forces experienced by the blocks. There is an acknowledgment of uncertainty regarding the correct magnitude of the contact force.

Chris0101
Messages
4
Reaction score
0

Homework Statement


Four blocks of masses 20kg, 30kg, 40kg, and 50kg are stacked on top of one another in an elevator in order of decreasing mass with the lightest mass on the top of the stack. The elevator moves downward with an acceleration of ##3.2m/s^2## . Find the contact force between the 30kg and 40kg masses.

Homework Equations



Newton's second law:
##F = ma##

In the case of the question at hand:
##F = mg + ma##

The Attempt at a Solution



Due to the fact that the elevator is moving downward with a positive acceleration, the total force that the top two blocks apply onto the 40kg block will be:

##F = mg + ma##
##F = (50kg)(9.81m/s^2) + (50kg)(3.2m/s^2)##
##F = 490.5N + 160.0N##
##F = 650.5N##


This shows that the force acting on the 40 kg block from the top two blocks (20kg & 30kg) is 650.5N. This downward magnitude of force is the amount of force that the 40kg block has to support which is also the normal force that the 40kg block. With that, the contact force between the 30kg and 40kg block is 650.5N

I'm not sure if this is correct. If someone can correct me on this question that would be great. Thanks for the help.
 
Physics news on Phys.org
Suppose that the downward acceleration was 9.81 m/s (that is, g). The elevator's acceleration would then match that due to gravity alone. That would mean the contents would essentially be in free-fall. Would the force then be 2g*50 kg ? In other words, do things feel heavier when the elevator accelerates downwards? Or do they feel lighter?
 
When the elevator is in free fall, one will experience weightlessness. With that said, if the the elevator is accelerating downward at a fraction of g, one's apparent weight will be less than his/her true weight. With your tip, I see where I went wrong and contact force between the 30kg and 40kg block should be the difference of the the two forces which is a magnitude of 330.5N.

Unfortunately, I do not have a reference to look up this answer, but is 330.5N the correct magnitude of the contact force between the 30kg and 40kg block, or am I forgetting something?
 
Chris0101 said:
is 330.5N the correct magnitude of the contact force between the 30kg and 40kg
Yes.
 
Thanks for the help
 

Similar threads

  • · Replies 17 ·
Replies
17
Views
2K
Replies
13
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
42
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K