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Stacked blocks on an accelerating elevator

  1. Dec 4, 2014 #1
    1. The problem statement, all variables and given/known data
    Four blocks of masses 20kg, 30kg, 40kg, and 50kg are stacked on top of one another in an elevator in order of decreasing mass with the lightest mass on the top of the stack. The elevator moves downward with an acceleration of ##3.2m/s^2## . Find the contact force between the 30kg and 40kg masses.

    2. Relevant equations

    Newton's second law:
    ##F = ma##

    In the case of the question at hand:
    ##F = mg + ma##


    3. The attempt at a solution

    Due to the fact that the elevator is moving downward with a positive acceleration, the total force that the top two blocks apply onto the 40kg block will be:

    ##F = mg + ma##
    ##F = (50kg)(9.81m/s^2) + (50kg)(3.2m/s^2)##
    ##F = 490.5N + 160.0N##
    ##F = 650.5N##


    This shows that the force acting on the 40 kg block from the top two blocks (20kg & 30kg) is 650.5N. This downward magnitude of force is the amount of force that the 40kg block has to support which is also the normal force that the 40kg block. With that, the contact force between the 30kg and 40kg block is 650.5N

    I'm not sure if this is correct. If someone can correct me on this question that would be great. Thanks for the help.
     
  2. jcsd
  3. Dec 4, 2014 #2

    gneill

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    Staff: Mentor

    Suppose that the downward acceleration was 9.81 m/s (that is, g). The elevator's acceleration would then match that due to gravity alone. That would mean the contents would essentially be in free-fall. Would the force then be 2g*50 kg ? In other words, do things feel heavier when the elevator accelerates downwards? Or do they feel lighter?
     
  4. Dec 4, 2014 #3
    When the elevator is in free fall, one will experience weightlessness. With that said, if the the elevator is accelerating downward at a fraction of g, one's apparent weight will be less than his/her true weight. With your tip, I see where I went wrong and contact force between the 30kg and 40kg block should be the difference of the the two forces which is a magnitude of 330.5N.

    Unfortunately, I do not have a reference to look up this answer, but is 330.5N the correct magnitude of the contact force between the 30kg and 40kg block, or am I forgetting something?
     
  5. Dec 5, 2014 #4

    haruspex

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    Yes.
     
  6. Dec 9, 2014 #5
    Thanks for the help
     
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