What is the Correct Concept for Solving the Stacked Blocks Problem?

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The discussion centers on the correct approach to solving the stacked blocks problem involving friction and acceleration. It emphasizes that when block X does not slip on block Y, both blocks must move together with the same acceleration. The applied force F affects block Y, while friction between the blocks influences their motion. The net horizontal force on block Y is the applied force minus the frictional force, which is crucial for determining acceleration. A free body diagram for each block is recommended for clarity in understanding the forces at play.
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Homework Statement


177cf5c7d0.png


Homework Equations


F= ma[/B]

The Attempt at a Solution


X does not slip. so friction exists. Friction should be equal to the force F applied so that according to Newton's 3rd law, the friction and F cancel out and X remains on Y.
Is this the right concept?
 
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Arun Raja said:

Homework Statement


177cf5c7d0.png


Homework Equations


F= ma[/B]

The Attempt at a Solution


X does not slip. so friction exists. Friction should be equal to the force F applied so that according to Newton's 3rd law, the friction and F cancel out and X remains on Y.
Is this the right concept?
No. F is applied on Y. The friction between X and Y acts also on X. So the net horizontal force exerted on Y is F-friction. If F and the friction cancel out Y does not accelerate. As X moves together with Y the whole system stays in rest or moves without acceleration. But the problem stated that it accelerates.
X does not slip on Y means that they move together, with the same acceleration.
ehild
 
That would be fine if the boxes moved at a constant speed ... but they don't.
Instead, draw a free body diagram for each block.
 
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