Standard errors in surface areas and volumes?

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SUMMARY

The discussion focuses on calculating the total surface area and volume of a copper cylinder, along with their respective standard errors using error propagation formulas. The cylinder has a length of 5.82 cm with an uncertainty of 0.06 cm and a radius of 2.53 cm with an uncertainty of 0.04 cm. The relevant formulas for volume and surface area are provided, specifically V = πr²ℓ for volume and the error propagation formula δf(x₁, ..., xₙ) = √(Σ(∂f/∂xᵢ δxᵢ)²). The calculated standard error in volume is noted as 2.88.

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I have to finish this one question that I have come across and I am having a bit of trouble figuring out where to go from what I havee done.
The Q is:

A copper cylinder is 5.82 +/- 0.06 cm long and has a radius of 2.53 +/- 0.04 cm. Using the appropraite formula,
Question Details
a) Find the total surface area of the cylinder and the standard error in the area .
b) Find the volume of the cylinder and the standard error in the volume.
c) Given that the density of copper is 8.96cm^-3, find the mass of the cylinder

We are to use error propagation formulas for this.

For part a and b I calculated the normals and for b- volume and used the formulae for product rules to calculate the error in volume and found it to be 2.88.

Can someone guide me through the process because I have the formulas and I plug in the values but I am not sure If i am right or not.

Thank you.
 
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CompuChip said:
Technically, the correct formula from error analysis is

\delta f(x_1, \cdots, x_n) = \sqrt{ \sum_{i = 1}^n \left( \frac{\partial f(x_1, \cdots, x_n)}{\partial x_i} \delta x_i \right)^2 }
where \delta x_i is the uncertainty in xi.

I prefer to remember just this formula and see how it applies in any particular problem. In this case, for example, the volume of the cilinder would be given by V = \pi r^2 \ell where r is the radius and \ell its length.
Since both of these have an uncertainty associated to them, you can calculate
\frac{\partial V}{\partial \ell} = \pi r^2, \quad \frac{\partial V}{\partial r} = 2 \pi r \ell
and simply plug in your values for r, \ell, \delta r \text{ and } \delta\ell.
 
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