Standing Wave Energy: Find Total Mech. Energy

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SUMMARY

The discussion focuses on calculating the total mechanical energy of a standing wave formed by two superimposed waves in a homogeneous string. The wave equations provided are y1 = Asin(wt-kx) and y2 = 2Asin(wt+kx). The kinetic energy (KE) of a small element is expressed as 1/2 u dx v^2, where u represents mass per unit length. Participants seek shortcuts for integration and clarification on how to incorporate potential energy (PE) into the total energy calculation.

PREREQUISITES
  • Understanding of wave mechanics and standing waves
  • Familiarity with kinetic energy calculations in physics
  • Knowledge of potential energy in wave systems
  • Ability to perform calculus, specifically integration
NEXT STEPS
  • Study the derivation of total mechanical energy in standing waves
  • Learn about potential energy in wave mechanics
  • Explore integration techniques for wave functions
  • Review the principles of superposition in wave theory
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics, and educators seeking to clarify concepts related to standing waves and energy calculations.

atavistic
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Homework Statement



A standing wave is maintained in a homogenous string of cross-sectional area a and density \rho . It is formed by the superposition of two waves traveling in opposite directions given by the equations

y1 = Asin(wt-kx)
y2 = 2Asin(wt +kx)

Find the total mechanical energy confined between the section corresponding to the adjacent antinodes.2. The attempt at a solution

The wave is given by y = Asin(wt-kx) + 2Asin(wt +kx)

KE of a small element is 1/2 u dx v^2 , where u = mass per unit length.

I find v by differentiating y wrt t.

Then I integrate with proper limits. But the integration looks outrageous looking at the simple answer. Is there any shortcut ? Also using above method we only get the KE, what about the PE?
 
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Hi atavistic! :smile:
atavistic said:
But the integration looks outrageous …

Show us! :smile:
 
Well can you tell me what I did is right or not and the thing about PE.
 

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