Standing Waves on a Violin String

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A violin string with a linear mass density of 1.00 g/m and a vibrating length of 40.0 cm produces a note with a wavelength of 60.0 cm. The discussion focuses on calculating the string tension using the fundamental frequency, which is derived from the speed of sound in air and the wavelength. It is clarified that there is a distinction between the wave speed in the string and the speed of sound in air, but the fundamental frequency remains consistent. The calculated tension in the string is found to be 209 N. Understanding these relationships is crucial for accurately determining string tension in musical instruments.
kikko
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Homework Statement



A violinist places her finger so that the vibrating section of a 1.00 g/m string has a length of 40.0 cm, then she draws her bow across it. A listener nearby in a 20oC room hears a note with a wavelength of 60.0 cm.

Homework Equations



Wavelengthm = (2L/m)
f1 = (v/2L) = (1/2L)(sqrt(Ts/(m/L)

The Attempt at a Solution

(((2Lf)^2)M)/LWhat am I doing something wrong?
 
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what are you trying to find, string tension?

I think you should find frequency using speed of sound and wavelength

you've assumed the frequency to be the fundamental frequency which I don't think is right...besides that I think there should also be some distinction between the speed of the wave traveling through the guitar string medium and the speed of sound through air, but I'm not too sure...
 
The book says to always use the fundamental frequency for stringed instruments, and from the text so far i really doubt it changes between the string and the air. Yes,I am trying to find string tension.
 
ok here's what I got

fundamental wavelength = 0.8
f=343/0.6 = 572 Hz

T/0.001 = (0.8 x 572)^2
T=209N

there is a distinction between velocity through air and the string, but the fundamental frequency as you said remains the same, thus we can use the speed of sound to find the fundamental frequency, multiply this by the wavelength on the string, and voila you have velocity through the string

hope that helps
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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