Static variable in static method - how to use?

[bikashdaga]

I wanted to declare a local variable inside a static method main().

My code looks like this -

class Operator
{
    static int a;
    public static void input() {
        Scanner in=new Scanner(System.in);
        System.out.println("Enter the number:");
        a=in.nextInt(); //this is nextInt and NOT Nextint
    }

    public static void output() {
        System.out.println("Number is:" + a);
    }

    public static void main (String[] args) throws java.lang.Exception
    {
        // your code goes here
        input();
        output();

    }
}

Is it something I am doing right?

I have read this [Spam link deleted by the Mentors] to understand if what I am writing is correct or not but I believe asking here will give me some sort of answer.

 

[Mark44]

I wanted to declare a local variable inside a static method main().

My code looks like this -

class Operator
{
    static int a;
    public static void input() {
        Scanner in=new Scanner(System.in);
        System.out.println("Enter the number:");
        a=in.nextInt(); //this is nextInt and NOT Nextint
    }

    public static void output() {
        System.out.println("Number is:" + a);
    }

    public static void main (String[] args) throws java.lang.Exception
    {
        // your code goes here
        input();
        output();

    }
}

Is it something I am doing right?

I have read this article [link removed] to understand if what I am writing is correct or not but I believe asking here will give me some sort of answer.

First off, your code sample is in Java, not Python. In your code tag you wrote this:
[code lang="python" title = "code"]

Please take a look at the post at the top of this section that describes how to use code tags in your sample code sections.

Second, your static variable is one that is shared by all instances of your Operator class. If one instance changes a, this will affect all instances of that class. Is that the behavior you want?

 

[jedishrfu]

This one instance of "a" will be especially painful if your Operator instances are used in a parallel context ie two instances processing at the same time one changes it but before it can use the changed "a" value the other instance changes it.

 

[bikashdaga]

I am really sorry for the mistake of tagging, thanks for pointing it out. Will make sure to tag properly.